Tailwind, Inc., produces high-quality but expensive training shoes for runners. The Tailwind shoe, which sells for...
Tailwind, Inc., produces high-quality but expensive training shoes for runners. The Tailwind shoe, which sells for $210, contains both gas- and liquid-filled compartments to provide more stability and better protection against knee, foot, and back injuries. Manufacturing the shoes requires 10 separate tasks. There are
400400
minutes available for manufacturing the shoes in the plant each day. Daily demand is
6464.
The information for the tasks is as follows:
|
Task |
Performance Time (mins) |
Predecessors |
|
|
A |
11 |
minus− |
|
|
B |
33 |
A |
|
|
C |
11 |
B |
|
|
D |
44 |
B |
|
|
E |
11 |
C, D |
|
|
F |
33 |
A |
|
|
G |
11 |
F |
|
|
H |
66 |
G |
|
|
I |
44 |
E, H |
|
|
J |
11 |
I |
|
a-b) The correct precedence relationship with one of the possible assignments of tasks using the "ranked positioned weight" to workstations is shown in
▼
Fig. 1
Fig. 2
Fig. 3
.c) The efficiency of the assembly line with 5 workstations shown in the figure chosen above=
nothing%
(enter your response as a percentage rounded to one decimal place).d) The idle time for the assembly line per cycle =
nothing
minute(s) (enter your response as a whole number).
font size increased by 4 Upper AA
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font size increased by 4 Upper II
font size increased by 4 Fig. 2Fig. 2
font size increased by 4 Upper GG
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font size increased by 4 Upper EE
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font size increased by 4 Upper FF
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font size increased by 4 Fig. 3Fig. 3
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x y graph
Enter your answer in each of the answer boxes.
Homework Answers
The total available time for task = 400 minutes
The demand = 64
Takt time = Total available time/Demand = 400/64 = 6.25 minutes
The precedence diagram is shown below
The total task time is 25 min. The cycle time is 6.25 min. This means that the number of workstations needed is 25/6.25 = 4.
The assignment practice is shown below.
| Task avl | Task asg | WS # | Time left | Task avl |
| A | A | 1 | 5.25 | B, F |
| B, F | F | 1 | 2.25 | B, G |
| B, G | B | 2 | 3.25 | C, D, G |
| C, D, G | G | 1 | 1.25 | C, D, H |
| C, D, H | H | 3 | 0.25 | C, D |
| C, D | D | 4 | 2.25 | C |
| C | C | 1 | 0.25 | E |
| E | E | 4 | 1.25 | I |
| I | I | 5 | 2.25 | J |
| J | J | 2 | 2.25 |
The final assignment is shown below
| WS | Tasks | Idle time |
| 1 | A, F, G, C | 0.25 |
| 2 | B, J | 2.25 |
| 3 | H | 0.25 |
| 4 | D, E | 1.25 |
| 5 | I | 2.25 |
The efficiency is 25/(5*6.25) = 0.8 or 80%
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