Question

Normal Distribution. The lifetime of a certain type of automobile tire (in thousands of miles) is...

Normal Distribution. The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mu = 42 and sigma = 5. What is the probability that a randomly chosen tire has a lifetime greater than 45 thousand miles? For this problem we want just the answer. Please give up to 4 significant decimal places, and use the proper rules of rounding.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer

using normalcdf

setting the following values

lower = 45

upper = 9999

mean = 42

sigma = 5

we get

P(X>45) = normalcdf(45,9999,42,5)

= 0.2743

Add a comment
Know the answer?
Add Answer to:
Normal Distribution. The lifetime of a certain type of automobile tire (in thousands of miles) is...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed...

    The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mean =μ39 and standard deviation =σ5. (a) What is the probability that a randomly chosen tire has a lifetime greater than 47 thousand miles? (b) What proportion of tires have lifetimes between 38 and 43 thousand miles? (c) What proportion of tires have lifetimes less than 44 thousand miles? Round the answers to at least four decimal places.

  • QUESTION 11 The lifetime of a certain type of automobile tire (in thousands of miles) is...

    QUESTION 11 The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mean N = 43 and standard deviation 0 = 5. What proportion of tires have lifetimes between 40 and 50 thousand miles? O 2.0000 0.3550 1.1935 O 0.6450

  • The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed...

    The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with a mean of 32 and a standard deviation of 4. Round to the second. a) Find the 50 percentile of tire lifetimes. b) Find the tire life that has 70% above it. c) Find the two tire lives that hold the middle 15% Lower Upper d) The tire company wants to guarantee that its tires will last a certain number of miles. What...

  • The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed...

    The lifetime of a certain type of automobile tire (in thousands of miles) is normally distributed with mean = 41 and standard deviation = 4. Use the TI-84 Plus calculator to answer the following. (a) Find the 21st percentile of the tire lifetimes. (b) Find the 73rd percentile of the tire lifetimes. (c) Find the first quartile of the tire lifetimes. (d) The tire company wants to guarantee that its tires will last at least a certain number of miles....

  • Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu...

    Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma = 14 inches. What is the value at the 50 percentile? For this problem we want just the answer. Please give up to 4 significant decimal places, and use the proper rules of rounding.

  • Suppose that the life span of a certain automobile tire is normally distributed with mu equals...

    Suppose that the life span of a certain automobile tire is normally distributed with mu equals 23,000 miles and sigmaequals2500 miles. ​(a) Find the probability that a tire will last between 28,000 and 30,500 miles. ​ (b) Find the probability that a tire will last more than 29,000 miles.

  • 3. The average number of miles (in thousands) that a car's tire will function before needing...

    3. The average number of miles (in thousands) that a car's tire will function before needing replacement is 72 and the standard deviation is 12. Suppose that 8 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of X? X ~ N( , ) ______ What is the distribution of x¯? x¯ ~ N( , ) ______ If a randomly selected individual tire is tested, find...

  • A normal population has mean = 9 and standard deviation -5. (a) What proportion of the...

    A normal population has mean = 9 and standard deviation -5. (a) What proportion of the population is less than 19? (b) What is the probability that a randomly chosen value will be greater than 4? Round the answers to four decimal places. Part 1 of 2 The proportion of the population less than 19 is Part 2 of 2 The probability that a randomly chosen value will be greater than 4 is : A normal population has mean =...

  • A study reports that the mean lifetime of a certain type of tire is 39500 miles...

    A study reports that the mean lifetime of a certain type of tire is 39500 miles with a standard deviation of 986 miles. Random samples of size 150 are taken from this type of tire. What would be the standard deviation of the distribution of the sample means? Round to two decimal places, if necessary.

  • The lifetime of a certain brand of tires is normally distributed. The average lifetime of a...

    The lifetime of a certain brand of tires is normally distributed. The average lifetime of a tire is 50,000 miles with a lifetime standard deviation of 8,400 miles. The probability that a randomly selected tire will last less than 45,000 miles is Tables Keypad 10 Points Answer 0.2758 0.0000 0.7242 0.2257 The resting heart rate (bpm) for a given conditioned athlete is a uniformly distributed random variable ranging between 40 and 60 bpm (beats per minute). What is the probability...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT