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1. Maltose, trehalose, and cellobiose are all disaccharides of glucose that differ in the nature of...

1. Maltose, trehalose, and cellobiose are all disaccharides of glucose that differ in the nature of the glycosidic bond attaching the two glucosyl residues. In maltose, the linkage is α(1→4); in trehalose, the linkage is α(1→1); in cellobiose the linkage is β(1→4). Based upon this information,which of these disaccharides is a non-reducing sugar? Explain your reasoning. Which of these disaccharides results from the breakdown of cellulose? Explain your reasoning. Which of these disaccharides results from the breakdown of amylose? Explain your reasoning.

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Answer #1

(a) Trehalose is a non-reducing sugar.

Explanation: If that anomeric has an OH-group, then it is a reducing sugar. This is because when the sugar is in the open configuration, that alcohol becomes a ketone or aldehyde which is able to reduce other compounds.

But here, in the trehalose, there is no OH-group present at the anomeric carbon due to α(1→1) glycoside linkage. Hence, trehalose is a non-reducing sugar.

(b) Cellobiose results from the breakdown of cellulose.

Explanation: Cellulose is a polymer of glucose molecules connected by β(1→4) glycosidic linkage. Hence, the breakdown of which results in the disaccharide containing β(1→4) glycosidic linkage, i.e. cellobiose.

(c) Maltose results from the breakdown of amylose.

Explanation: Amylose is a polymer of glucose molecules connected by α(1→4) glycosidic linkage. Hence, the breakdown of which results in the disaccharide containing α(1→4) glycosidic linkage, i.e. maltose.

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