If 62.5 moles of an ideal gas is at 6.39 atm at 16.00 °C, what is the volume of the gas?
According to Ideal gas law,
PV = nRT
V = nRT / P
Given
Pressure P = 6.39 atm
No. of moles of gas n = 62.5 moles
Temperature T = 16.00 o C = 16.00 o C + 273 K = 289 K
Universal gas constant R =
Volume V = ?
V = nRT / P
= (62.5 mol * 0.08205 L atm / K mol * 289 K ) / 6.39 atm
= 231.929285 L = 232 L
Volume V = 231.929285 L = 232 L
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