ZuoTi.Pro
Question

Consider the sample of 600 past negligence cases. Suppose you are willing to let the 80%...

Consider the sample of 600 past negligence cases. Suppose you are willing to let the 80% estimate be within .03 (3%) of the true proportion. You are willing to assume a 90% confidence. Construct a 90% confidence interval on the estimate of 80%. How would you interpret it?

math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
Consider the sample of 600 past negligence cases. Suppose you are willing to let the 80%...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • please don't round mid calculation(: · Question 16 You want to obtain a sample to estimate...

    please don't round mid calculation(: · Question 16 You want to obtain a sample to estimate a population proportion. At this point in time, you have no for the population proportion. You would like to be 90% confident that you esimate is within 0.05 of the true population proportion. How large of a sample size is required? Do not round mid-calculation. A group of researchers is interested in middle school students and their willingness to appear to stand out. A...

  • 2pts, 1 for work) A 2011 NBC News survey found that 80% of a sample of...

    2pts, 1 for work) A 2011 NBC News survey found that 80% of a sample of 4500 American teens said they owned an MP3 player such as an ipod. Assume the sample is an SRS. Based on the sample, the 90% confidence interval for the proportion of teens who own an MP3 player is: a. 0.80 ± 0.0060 b. 0.80 ± 0.0117 c. 0.80 ± 0.0098 d. 0.80 ± 0.0071 3. (2pts, 1 for work) If we computed an 80%...

  • Suppose you want to estimate the true proportion of U.S. women with a gluten sensitivity. In...

    Suppose you want to estimate the true proportion of U.S. women with a gluten sensitivity. In a large study using a random sample of 2500 U.S. women, 163 women, 163 women had a gluten sensitivity. 1. Calculate a 98% confidence interval for the true proportion of women with a gluten-sensitivity. As in the last assignment, show all the steps. 2. Interpret the confidence LEVEL. 3. How many women need to be examined in order to estimate the true proportion to...

  • in a random sample of 150 turtles, it is found that 30 have light-coloured shells. let...

    in a random sample of 150 turtles, it is found that 30 have light-coloured shells. let p be the population proportion of turtles that have light-coloured shells. i) using our observations as a pilot study, estimate the sample size needed to construct confidence interval such that we are 90% confident that the sample proportion will be within 0.01 of the true population proportion p. ii) if we were to test the hypothesis H0 : p <= 0.15,H1 ; p >...

  • A random sample of 328 medical doctors showed that 172 had a solo practice. (a) Let...

    A random sample of 328 medical doctors showed that 172 had a solo practice. (a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.) (b) Find a 90% confidence interval for p. (Use 3 decimal places.) lower limit upper limit Give a brief explanation of the meaning of the interval. 90% of the confidence intervals created using this method would include the true proportion of...

  • In a survey conducted by CNN, 130 of the 250 people surveyed have a savings account....

    In a survey conducted by CNN, 130 of the 250 people surveyed have a savings account. (a) Construct a 90% confidence interval to estimate the true population proportion of people that have a savings account. (b) Suppose CNN is going to conduct this survey again. If we want our estimate to be within 3% of the true population proportion with 90% confidence, how many people do we need to sample?

  • A random sample of 326 medical doctors showed that 170 had a solo practice. (a) Let...

    A random sample of 326 medical doctors showed that 170 had a solo practice. (a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.) (b) Find a 90% confidence interval for p. (Use 3 decimal places.) lower limit upper limit Give a brief explanation of the meaning of the interval. 90% of the confidence intervals created using this method would include the true proportion of...

  • 1. A prison official wants to estimate the proportion of cases of recidivism. Examining the records...

    1. A prison official wants to estimate the proportion of cases of recidivism. Examining the records of 238 convicts, the official determines that there are 92 cases of recidivism. Find the lower limit of the 90% confidence interval estimate for the population proportion of cases of recidivism. (Round to 3 decimal places.) 2. A prison official wants to estimate the proportion of cases of recidivism. Examining the records of 157 convicts, the official determines that there are 47 cases of...

  • Section 9.1 Estimating a Population Proportion Bird Flu: As a potential worldwide pandemic, avian influenza H5N1...

    Section 9.1 Estimating a Population Proportion Bird Flu: As a potential worldwide pandemic, avian influenza H5N1 (commonly called the bird flu) poses a serious health risk. As of January 24, 2012, there have been 583 human cases of this virus in the world. Of these cases, 344 have resulted in death. Consider the outcomes of these cases as a random sample of all possible outcomes. Find a point estimate for the proportion of people who would die if infected with...

  • Assume that a sample is used to estimate a population proportion p. Find the 80% confidence...

    Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 380 with 125 successes. Enter your answer as an inequality using decimals (not percents) accurate to three decimal places. We wish to estimate what percent of adult residents in a certain county are parents. Out of 500 adult residents sampled, 195 had kids. Based on this, construct a 90% confidence interval for the proportion of adult residents who...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT