A simple random sample consists of 65 lengths of piano wire that were tested for the amount of extension under a load of 30 N. The average extension for the 65 lines was 1.104 mm and the standard deviation was 0.030 mm. Let μ represent the mean extension for all specimens of this type of piano wire.
a)Find the P-value for testing H0 : μ ≤ 1.1 versus H1 : μ > 1.1. Round the answer to four decimal places.
b)Either the mean extension for this type of wire is greater than 1.1 mm, or the sample is in the most extreme ( ) % of its distribution. Round the answer to two decimal places.
The formula for the test statistic is:
X-bar = 1.104
s = 0.030
n = 65
Hence, t = (1.104 - 1.1)/(0.030/√65) = 1.08
The p-value associated with t = 1.08 and df = n - 1 = 64 is 0.1421
b) The question is not clear but we can definitely conclude that we do not reject the null hypothesis. We say that the mean extension for this type of wire is not greater than 1.1 mm. The sample is in the most extreme 14.21% of its distribution.
A simple random sample consists of 65 lengths of piano wire that were tested for the...
Testing: H0:μ=43.4 H1:μ<43.4 Your sample consists of 37 subjects, with a mean of 42.9 and standard deviation of 2.98. Calculate the test statistic, rounded to 2 decimal places. t=
A random sample of 105 observations produced a sample mean of 32. Find the critical and observed values of z for the following test of hypothesis using α=0.1. The population standard deviation is known to be 9 and the population distribution is normal. H0: μ=28 versus H1: μ>28. Round your answers to two decimal places. zcritical = zobserved =
Consider H0: μ=72 versus H1: μ>72. A random sample of 16 observations taken from this population produced a sample mean of 75.4. The population is normally distributed with σ=6. a. Calculate the p-value. Round your answer to four decimal places.
A simple random sample of 60 adults is obtained from a normally distributed population, and each person's red blood cell count (in cells permicroliter) is measured. The sample mean is 5.27 and the sample standard deviation is 0.53. Use a 0.01 significance level and the given calculator display to test the claim that the sample is from a population with a mean less than 5.4, which is a value often used for the upper limit of the range of normal...
Testing: H0:μ=21.41H0:μ=21.41 H1:μ≠21.41H1:μ≠21.41 Your sample consists of 46 subjects, with a mean of 21.5 and standard deviation of 3.58. Calculate the test statistic, rounded to 2 decimal places. t=t= Suppose are running a study/poll about the proportion of men over 50 who regularly have their prostate examined. You randomly sample 136 people and find that 75 of them match the condition you are testing. Suppose you are have the following null and alternative hypotheses for a test you are running:...
Testing: Ho : μ H1 : μ 18.015 18.015 Your sample consists of 29 subjects, with a mean of 19.4 and standard deviation of 4.57. Calculate the test statistic, rounded to 2 decimal places.
Testing: 34.29 0 : μ H1 : μ > 34.29 Your sample consists of 6 subjects, with a mean of 34.9 and standard deviation of 1.82 Calculate the test statistic, rounded to 2 decimal places. t34.29
A new concrete mix is being designed to provide adequate compressive strength for concrete blocks. The specification for a particular application calls for the blocks to have a mean compressive strength μ greater than 1350 kPa. A sample of 100 blocks is produced and tested. Their mean compressive strength is 1356 kPa and their standard deviation is 70 kPa. A test is made of H0 : µ ≤ 1350 versus H1 : µ > 1350. a. Find the P-value. Round...
Given the following hypotheses: H0: μ = 600 H1: μ ≠ 600 A random sample of 16 observations is selected from a normal population. The sample mean was 609 and the sample standard deviation 6. Using the 0.10 significance level: State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject H0 when the test statistic is outside the interval ( , ). ? Compute the value of the test...
In a simple random sample of size 65, there were 37 individuals in the category of interest. Part: 0 / 4 Part 1 of 4 (a) Compute the sample proportion P. Round the answer to at least three decimal places. The sample proportion is Х 5 Part 2 of 4 (b) Are the assumptions for a hypothesis test satisfied? Explain. Yes the number of individuals in each category is smaller than 10. Part: 2/4 Part 3 of 4 (C) It...