Refrigerant 134a enters a well-insulated nozzle at 14 bar, 60°C, with a velocity of 40 m/s...
Refrigerant 134a enters a well-insulated nozzle at 14 bar, 60°C, with a velocity of 40 m/s and exits at 1.2 bar with a velocity of 460 m/s. For steady-state operation, and neglecting potential energy effects, determine: (a) the exit temperature, in K.
Homework Answers
From Steady state energy equation,
Q = Wcv+ change in K.E + change in P.E + change in Enthalpy
As it is given that the nozzle is well insulated and we have to neglect P.E effect
we have,
change in K.E + change in Enthapy = 0
1/2[m(v22 - v12)] = - m(h2-h1)
1/2(v22 - v12) = (h1-h2) = cp(t1-t2)
given : v1=40 m/s , v2= 460m/s , t1= 273+60=333 K
From psychomateric tables , At P=14 bar and temp = 600C , Isobaric Specific Enthalpy = 1.2092 kJ/kg-K
1/2(4602-402) = 1.2092*1000(333-t2)
t2 = 246.165 K
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