(Please legibly write out all steps. Please don't type out the answer. In addition, please include the physics formula that you'll use in order to solve the problem. Thank you. )
How much ice is required to bring the temperature of 0.75 L of soda from 35°C to 0°C? (Lf= 3.33x10^5 J/kg, Cwater= 4186 J/kg, °C, Mass of 1 L of water= 1 kg (95% of soda is water). The answer should be in kilograms.
a) 0.25 kg
b) 0.33 kg
c) 0.28 kg
d) 2.5 kg
heat absorbed by ice = heat released by water soda
m ( L) = M Cw dT
m * 3.32* 10^5 = 0.75** 4186* ( 35 - 0)
m = 0.33 kg
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(Please legibly write out all steps. Please don't type out the answer. In addition, please include...
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