Question

ince the mid-1960s, the overall free throw percent at all college levels, for both men and women, has remained pretty consistent. For men, players have shot roughly 69% with the season percent never falling below 67% or larger than 70%. Assume that 300,000 free throws will be attempted in the upcoming season.

Fill in the blanks.

If the population proportion, p = 0.69,

The mean, μ, of X is -------

The standard deviation, σ, of X is (round to 4 decimal places) --------

Answer 1

solution:-

given that population proportion , p = 0.69 and n = 300,000

The mean, μ, of X is 0.69

The standard deviation, σ, of X is = sqrt(p*(1-p)/n)

   = sqrt(0.69*(1-0.69)/300,000)

    = 0.0008