which of the following would be a correct definition for pKa -the inverse log (1/log value...
which of the following would be a correct definition for pKa
-the inverse log (1/log value of the Ka
-the pH of the acidic solution when the acidic form has been completely converted to its conjugate base form
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which of the following would be a correct definition for pKa
-the inverse log (1/log value...
Need help on questions 1-3 Henderson-Hasselbalch: pH=pka + Log( [base]/(acid] ) 1. The value of Ka...
Need help on questions 1-3
Henderson-Hasselbalch: pH=pka + Log( [base]/(acid] ) 1. The value of Ka of nitrous acid (HNO2) is 4.6 x 104 M. Calculate the pH and the concentration of [H3O+] in a 0.02M aqueous solution of HNO2(aq). 2. Label conjugate acid-base pairs: HNO2(aq) + H2O → H30* + NO2 (aq) 3. What will happen to the reaction equilibrium if we increase the pressure in the reaction vessel? H2(g) + 12(e) → 2 HI(g)
2-Aminophenol is fairly acidic having a pKa value of ~4.8. Which of the structures shown below...
2-Aminophenol is fairly acidic having a pKa value of ~4.8. Which
of the structures shown below (labeled I - IV) is not a
valid resonance form of the expected conjugate base.
2-Aminophenol is fairly acidic having a pka value of 4.8. Which of the structures shown below (labeled I - IV) is not a valid resonance form of the expected conjugate base.
Lab 5 Buffers 1. Dissolved ions in salt solutions can act as acids or bases and...
Lab 5 Buffers 1. Dissolved ions in salt solutions can act as acids or bases and react with water to produce hydronium ions or hydroxide ions that contribute to the pH of the salt solution. Since strong acids and strong bases completely ionize in solution, the reverse reaction essentially does not occur, meaning that the resulting conjugate base of a strong acid or conjugate acid of a strong base do NOT act as acids or bases. Ions that are conjugate...
Equations pH=-log[H3O+]; pOH= -log[OH]; pKw=14.00=pH+POH; Ka-[H3O+][A-[HA]; Kb=[BH+][OH-)[B); pKa=-log Ka; Ka. Kb=Kw Constants Ka (HS-)=1x10-19; Ka (HF)...
Equations pH=-log[H3O+]; pOH= -log[OH]; pKw=14.00=pH+POH; Ka-[H3O+][A-[HA]; Kb=[BH+][OH-)[B); pKa=-log Ka; Ka. Kb=Kw Constants Ka (HS-)=1x10-19; Ka (HF) 7.2x10-4; Ka ([Al(H20).]+)7.9x10-6; Ka (H3PO4)=7.5x10-2: Ka (HPO42-) =3.6x10-13; Ka (HCI)=Huge; Ka(Na+)=tiny; Ka(Cl-)tiny; Kb(NH3)=1.8x10-5; Kw=1x10-14 1) Calculate the pH of aqueous 0.25M HCl and 0.25M HF solutions. 2) Complete the following tables for aqueous solutions of conjugate acid-base pKa pKb Kb 1.3x10-4 35 3) Complete the following table for aqueous solutions DHL TH+) OH) pOH 1x102 4) Calculate the pH of aqueous 0.15M Ba(OH)2 and...
4.13 Just as pH is the negative logarithm of [H3O+], pKa is the negative logarithm of...
4.13 Just as pH is the negative logarithm of [H3O+], pKa is the negative logarithm of Ka, pKa=−logKa The Henderson-Hasselbalch equation is used to calculate the pH of buffer solutions: pH=pKa+log[base][acid] Notice that the pH of a buffer has a value close to the pKa of the acid, differing only by the logarithm of the concentration ratio [base]/[acid]. Part B How many grams of dry NH4Cl need to be added to 2.10 L of a 0.400 M solution of ammonia,...
7. The p-fluorobenzoic acid (C6FH5CO2H) has a pka = 4.14 a) Compute the Ka value for...
7. The p-fluorobenzoic acid (C6FH5CO2H) has a pka = 4.14 a) Compute the Ka value for this acid. (4 points) b) Compute the Ko value for the conjugate base of this acid above and write out the equilibrium of the conjugate base. (6 points) c) Calculate the pH of a 0.0572 Molar sodium fluorobenzoate ( Na C6FH5CO2 )solution. Use the equilibrium in b to start this problem and the Kb from above. (8 points)
Which of the following acids, whose pKa values are given next to them, would have the...
Which of the following acids, whose pKa values are given next to them, would have the strongest conjugate base? pKa a) H2SO4 b) CH3COOH 4.8 c) HS 12.9 d) NH* 2.0 9.2 Reaction of a carboxylic acid with an alcohol produces: a) an alkane b) an ester c) a ketone d) an amide During the neutralisation of a weak acid by a strong base the pH of the solution equals the pKa of the acid: a) at the beginning of...
Hydrogen sulfide has a pKa of 7.05. If hydrocyanic acid has a pKa of 9.21 and...
Hydrogen sulfide has a pKa of 7.05. If hydrocyanic acid has a pKa of 9.21 and fluoroacetic acid has a pKa of 2.59, which one would act as a base in the presence of hydrogen sulfide instead of an acid? A. Does the acid react with the lower pKa or the base? B. Which of the two acids would act as a base in the presence of hydrogen sulfide and why? C. Of the three acids mentioned, which one would...
Which of the following 0.10 M aqueous solutions gives the highest pH? A) CH3COOH (pKa =...
Which of the following 0.10 M aqueous solutions gives the highest pH? A) CH3COOH (pKa = 4.75) B) HF (PK:= 3.45) C) H3PO4 (pKal = 2.12) D) HCIQ (Ka=2.00) E) Since all are acids, the pH is the same for all solutions. 5. Which one of the following salts gives an acidic aqueous solution? A) CsNO3 B) CaCl2C ) LiF D) Cr(CIO4)3 E) NaCH3CO2 6. 7. All of the following are strong acids except A) HCIQB) HC104 C) HI D)...
9) Which one of the following pairs cannot be mixed together to form a buffer solutions...
9) Which one of the following pairs cannot be mixed together to form a buffer solutions A) KOH, HNO2 B) H2S03. KHSO3 C) HONH2, HONH3CI D) NaCI, HCI E) RbOH, HF 10) The Henderson-Hasselbalch equation is acid) acid] A) pH- pKa log basel base] D) pH - pKaobase [acid 11) HA is a weak acid. Which equilibrium corresponds to the equilibrium constant Kp for A- A) A (aq) H30+ (aq) HA (aq) H20 0) B) HA (aq) + OH-(aq) 근...
Need help on questions 1-3
Henderson-Hasselbalch: pH=pka + Log( [base]/(acid] ) 1. The value of Ka of nitrous acid (HNO2) is 4.6 x 104 M. Calculate the pH and the concentration of [H3O+] in a 0.02M aqueous solution of HNO2(aq). 2. Label conjugate acid-base pairs: HNO2(aq) + H2O → H30* + NO2 (aq) 3. What will happen to the reaction equilibrium if we increase the pressure in the reaction vessel? H2(g) + 12(e) → 2 HI(g)
2-Aminophenol is fairly acidic having a pKa value of ~4.8. Which
of the structures shown below (labeled I - IV) is not a
valid resonance form of the expected conjugate base.
2-Aminophenol is fairly acidic having a pka value of 4.8. Which of the structures shown below (labeled I - IV) is not a valid resonance form of the expected conjugate base.
Equations pH=-log[H3O+]; pOH= -log[OH]; pKw=14.00=pH+POH; Ka-[H3O+][A-[HA]; Kb=[BH+][OH-)[B); pKa=-log Ka; Ka. Kb=Kw Constants Ka (HS-)=1x10-19; Ka (HF) 7.2x10-4; Ka ([Al(H20).]+)7.9x10-6; Ka (H3PO4)=7.5x10-2: Ka (HPO42-) =3.6x10-13; Ka (HCI)=Huge; Ka(Na+)=tiny; Ka(Cl-)tiny; Kb(NH3)=1.8x10-5; Kw=1x10-14 1) Calculate the pH of aqueous 0.25M HCl and 0.25M HF solutions. 2) Complete the following tables for aqueous solutions of conjugate acid-base pKa pKb Kb 1.3x10-4 35 3) Complete the following table for aqueous solutions DHL TH+) OH) pOH 1x102 4) Calculate the pH of aqueous 0.15M Ba(OH)2 and...
7. The p-fluorobenzoic acid (C6FH5CO2H) has a pka = 4.14 a) Compute the Ka value for this acid. (4 points) b) Compute the Ko value for the conjugate base of this acid above and write out the equilibrium of the conjugate base. (6 points) c) Calculate the pH of a 0.0572 Molar sodium fluorobenzoate ( Na C6FH5CO2 )solution. Use the equilibrium in b to start this problem and the Kb from above. (8 points)
Which of the following acids, whose pKa values are given next to them, would have the strongest conjugate base? pKa a) H2SO4 b) CH3COOH 4.8 c) HS 12.9 d) NH* 2.0 9.2 Reaction of a carboxylic acid with an alcohol produces: a) an alkane b) an ester c) a ketone d) an amide During the neutralisation of a weak acid by a strong base the pH of the solution equals the pKa of the acid: a) at the beginning of...
Which of the following 0.10 M aqueous solutions gives the highest pH? A) CH3COOH (pKa = 4.75) B) HF (PK:= 3.45) C) H3PO4 (pKal = 2.12) D) HCIQ (Ka=2.00) E) Since all are acids, the pH is the same for all solutions. 5. Which one of the following salts gives an acidic aqueous solution? A) CsNO3 B) CaCl2C ) LiF D) Cr(CIO4)3 E) NaCH3CO2 6. 7. All of the following are strong acids except A) HCIQB) HC104 C) HI D)...
9) Which one of the following pairs cannot be mixed together to form a buffer solutions A) KOH, HNO2 B) H2S03. KHSO3 C) HONH2, HONH3CI D) NaCI, HCI E) RbOH, HF 10) The Henderson-Hasselbalch equation is acid) acid] A) pH- pKa log basel base] D) pH - pKaobase [acid 11) HA is a weak acid. Which equilibrium corresponds to the equilibrium constant Kp for A- A) A (aq) H30+ (aq) HA (aq) H20 0) B) HA (aq) + OH-(aq) 근...
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