Ans :
Number of moles of bromine = mass / molar mas
= 21.6 g / 79.904 g/mol = 0.27 mol
number of mol of chlorine = mass / molar mass
= 9.6 g / 35.453 g/mol = 0.27 mol
Since equimolar amounts of both the reagents are present , the number of mol of product bromine monochloride formedwill be 0.27 mol
Mass of bromine monochloride = mol x molar mass
= 0.27 mol x 115.357 g/mol
= 31.1 grams
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