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The vapor pressure for pure ethanol and pure propane is measured as a function of temperature....

The vapor pressure for pure ethanol and pure propane is measured as a function of temperature. In each case, a graph of the ln of the vapor pressure versus 1/T is found to be a straight line. The slope of the line for ethanol is − 4643 K, and the slope of the line for propane is − 1888 K. Determine ΔHvap for propane.

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Answer #1

The relation between K and T is:

K = A*e^(-Ho/RT)

taking ln on both sides, above expression becomes,

ln K = ln A - Ho/RT

So, slope between ln K and 1/T will have a value of -Ho/R and y intercept is ln A

Here slope = -1888

So,

-Ho/R = -1888

-Ho/8.314 = -1888

Ho = 15697 J/mol

= 15.7 KJ/mol

Answer: 15.7 KJ/mol

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