Balanced chemical equation is:
CaCO3 + 2 HCl ---> CaCl2 + CO2 + H2O
lets calculate the mol of CaCO3
volume , V = 2 L
use:
number of mol,
n = Molarity * Volume
= 0.1*2
= 0.2 mol
According to balanced equation
mol of HCl reacted = (2/1)* moles of CaCO3
= (2/1)*0.2
= 0.4 mol
This is number of moles of HCl
Molar mass of HCl,
MM = 1*MM(H) + 1*MM(Cl)
= 1*1.008 + 1*35.45
= 36.458 g/mol
use:
mass of HCl,
m = number of mol * molar mass
= 0.4 mol * 36.46 g/mol
= 14.58 g
Answer: 14.6 g
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