Question

Given: constant radius circular curve in plan view.
Delta = 40 deg 00 min 00 sec Right
R = 1000.000 meters
PC Station = 10+00.000
Azimuth from the PC to the PI = 45 deg 00 min 00 sec
PC Northing and Easting = 0.0000 m


If a total station was set up at the PC of the curve, backsighting the PI, and 0 set, what would the angle right and horizontal distance be to layout station 12+00.000 on the curve? Round the angle to the nearest second and the distance to the nearest .001 meters.

Question 2 options:

	1) 7d 37m 13s right and 698.130 meters
	2) 11d 27m 33s right and 200.000 meters
	3) 5d 43m 46s right and 199.668 meters
	4) 40d 00m 00s right and 200.000 meters

Answer 1

Length along the curve to the layout staion is initially found out by subtracting chainage.

From that deflection angle between tangent at PC and tangent at layout station is found out.

From that required angle is found out and following horizontal distance to the layout station is calculated,

Answer is option 3.

Solution is uploaded below.