How many moles of sodium fluoride (used in water fluoridation and manufacture of insecticides) are needed to form 2.84 moles of sulfur tetrafluoride?
3SCl2(l) + 4NaF(s) → SF4(g) + S2Cl2(l) + 4NaCl(s)
a. 2.13 mol
b. 0.71 mol
c. 2.84 mol
d. 11.36 mol
e. 1.42 mo
3SCl2(l) + 4NaF(s) → SF4(g) + S2Cl2(l) + 4NaCl(s)
Molecular weight of SCl2 = 102.97
Molecular weight of NaF = 41.988
Molecular weight of SF4= 108.07
4 moles of NaF produces 1 mole of SF4 then
How many moles of NaF required to produce 2.84 moles of SF4
Therefore, amount of NaF required = (2.84*4)/1 = 11.36 mole
Thus 11.36 moles of NaF is required to produce 2.84 moles of SF4
How many moles of sodium fluoride (used in water fluoridation and manufacture of insecticides) are needed...
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