Question

Show how each of the following floating-point values would be stored for -127.625 using IEEE-754 single precision be sure to indicate the sign bit, the exponent, and the significand fields

Answer 1

-127.625 in simple binary => 1111111.101
so, -127.625 in normal binary is 1111111.101 => 1.11111110100000000000000 * 2^6

single precision:
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sign bit is 1(-ve)
exp bits are (127+6=133) => 10000101
frac bits are 11111110100000000000000

so, -127.625 in single-precision format is 1 10000101 11111110100000000000000
in hexadecimal it is 0xC2FF4000