a)
Usin equilibrium of force
Fn = mg
Fn = 10 x 9.8 = 98 N
b)
Using equilibrium of force
Fn' = Fn + mg
Fn' = 98 + (10) (9.8)
Fn' = 196 N
c)
F = force by the table
F' = normal force by the boxes above
Using equilibrium of force
F = mg + F'
F = mg + 9 mg
F =10 mg
F = (10) (10) (9.8)
F = 980 N
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