In the Health ABC Study, 540 subjects owned a pet and 1965 subjects did not. Among the pet owners, there were 300 women; 987 of the non-pet owners were women. Find the proportion of pet owners who were women. Do the same for the non-pet owners. (Be sure to let Population 1 correspond to the group with the higher proportion so that the difference will be positive. Round your answers to three decimal places.)
p̂_{1} | = |
p̂_{2} | = |
Give a 95% confidence interval for the difference in the two
proportions. (Do not use rounded values. Round your final answers
to three decimal places.)
In the Health ABC Study, 540 subjects owned a pet and 1965 subjects did not. Among...
I need help with the last part of this problem. I posted the first parts that I already have the answers to also but only need help with the final part. Thanks. In 1950, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?" Of the 1100 adults surveyed, 352 indicated that they were total abstainers. In a recent survey, the same question was asked of 1100 adults and...
The authors of the article "Adjuvant Radiotherapy and Chemotherapy in Node-Positive Premenopausal Women with Breast Cancer"† reported on the results of an experiment designed to compare treating cancer patients with chemotherapy only to treatment with a combination of chemotherapy and radiation. Of the 154 individuals who received the chemotherapy-only treatment, 76 survived at least 15 years, whereas 98 of the 164 patients who received the hybrid treatment survived at least that long. With p1 denoting the proportion of all such...
In 1950, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?" Of the 1100 adults surveyed, 352 indicated that they were total abstainers. In a recent survey, the same question was asked of 1100 adults and 286 indicated that they were total abstainers. (a) Determine the sample proportion for each sample. The proportions of the adults who took the 1950 survey and the recent survey who were total...
taking the drug. The study included 9807 overweight or obese subjects with pre-existing cardiovascular disease and/or type 2 diabetes. The subjects were randomly assigned to (4908 subjects) or a placebo (4899 subjects) ) in a double-blind fashion. The primary outcome measured was the occurrence of any of the following events: nonfatal a myocardial infarction or stroke, resuscitation after cardiac arrest, or cardiovascular death. The primary outcome was observed in 561 subjects in the subitramine group and 493 subjects in the...
(2 points) In a study of red/ men and 2100 women are randomly selected and tested. Among the men, 44 have red/green color blindness. Among the women, 5 have red/green color blindness. Test the claim that men have a higher rate of red/green color blindness. (Note: Type P-m not = p-w for the proportions are not equal, p_m > p_w for the proportion of men with color blindness is larger, p_m < p_w ,for the proportion of men is smaller,...
Two random samples are taken, one from among UVA students and the other from among UNC students. Both groups are asked if academics are their top priority. A summary of the sample sizes and proportions of each group answering yes'' are given below: UVA (Pop. 1):UNC (Pop. 2):n1=80,n2=99,p^1=0.736p^2=0.602 Find a 97.9% confidence interval for the difference p1−p2 of the population proportions. (Give your answer as two values inside parentheses, separated by a comma, and rounded to at least three decimal...
Question 12 of 31 (1 point) View problem in a pop-up 9.4 Section Exercise 16 National statistics show that 23% of men smoke and 18.5% of women do. A random sample of 159 men indicated that 40 were smokers, and of 129 women surveyed, 17 indicated that they smoked. Part 1 out of 2 Construct a 90% confidence interval for the true difference in proportions of male and female smokers. Use P, for the proportion of men who smoke. Round...
Question 11 of 31 (1 point) 9.4 Section Exercise 15 (table) A recent random survey of 105 individuals in Michigan found that 75 drove to work alone. A similar survey of 120 commuters in New York found that 64 drivers drove alone to work. Find the 95% confidence interval for the difference in proportions. Use ê, for the proportion of Michigan drivers who drive alone to work. Round your answers to three decimal places. <P1-P2 Question 12 of 31 (1...
In a study of red/green color blindness, 1000 men and 2550 women are randomly selected and tested. Among the men, 90 have red/green color blindness. Among the women, 8 have red/green color blindness. Test the claim that men have a higher rate of red/green color blindness. (Note: Type p_mnot=p_w for the proportions are not equal, p_m>p_w for the proportion of men with color blindness is larger, p_m (a) State the null hypothesis: (b) State the alternative hypothesis: (c) The test...
Two random samples are taken, one from among UVA students and the other from among UNC students. Both groups are asked if academics are their top priority. A summary of the sample sizes and proportions of each group answering yes'' are given below: UVA (Pop. 1): UNC (Pop. 2): n 1 =84, n 2 =81, p ^ 1 =0.749 p ^ 2 =0.555 UVA (Pop. 1):n1=84,p^1=0.749UNC (Pop. 2):n2=81,p^2=0.555 Find a 93.3% confidence interval for the difference p1−p2 of the population proportions. (Give your...