A parallel-plate capacitor has plates with an area of 250 cm2 separated by 1.0 mm. What is the electric field between the plates when they are charged with 7.000×10-7 C?
Solution:
Using the formula,
=> E = Q/(e0 * A)
=> E = 7 * 10^-7 /(8.85 * 10^-12 * 250 * 10^-4)
=> E = 7 * 10^9 /(8.85 * 250)
=> E = 3.16 * 10^6 N/C
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