What is the theoretical yield (in moles) of MgO that can be formed if you react 3.2 mol of O2 with an excess of magnesium? 2Mg(s) + O2(g) → 2MgO(s)
Theoretical yield:
3.2 mole O2 X 2 mole of MgO/1 mole O2 = 6.4 mole of MgO.
Or
1 mole of O2 produced 2 moles MgO -from balanced equation
3.2 moles of O2 produce X mole of MgO
X= 3.2x2/1= 6.4 mole MgO
What is the theoretical yield (in moles) of MgO that can be formed if you react...
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reaction that has a theoretical yield of
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