A thin-walled hollow cylinder is rolling on a surface. What fraction of its total kinetic energy is in the form of rotational kinetic energy about the center of mass?
The answer is not 2/5.
thin-walled hollow cylinder means moment of inertia , I is given as
I = mr2
v = rw ( no slip condition)
so,
rotational kinetic energy, KR = 1/2 * I * w2
KR = 1/2 * mr2 * v2 / r2
KR = 1/2mv2
so,
fraction = KR / KT where KT is total kinetic energy
fraction = 1/2mv2 / 1/2mv2 + 1/2mv2
fraction = 1/2
A thin-walled hollow cylinder is rolling on a surface. What fraction of its total kinetic energy...
A hoop (thin walled hollow cylinder) of mass 2.3 kg, radius 0.37 m, is rotating at 6.39 radians/s about the symmetric axis. Calculate its rotational kinetic energy in Joules to 2 significant figures Answer: I
A uniform cylinder of radius r15.0 cm and mass m 1.70 kg is rolling without slipping on a horizontal tabletop. The cylinder's center of mass is observed to have a speed of 4.60 m/s at a given instant. (a) What is the translational kinetic energy of the cylinder at that instant? J (b) What is the rotational kinetic energy of the cylinder around its center of mass at that instant? J (c) What is the total kinetic energy of the...
Problem #1 (3+1+1+1-6 points) A thin-walled hollow cylinder is released from rest and rolls down the hill that slops downward at 500 from the horizontal without slipping. The mass of the cylinder is 3 kg and its radius is 0.5 m. hemomento mertiited linder is 1 -M Re Find: (a) the minimum value of the coefficient of static friction between the cylinder and the hill for no slipping to occur (1 point); (b) using the answer to part (a) calculate...
Interactive Solution 9.53 offers a model for solving problems of this type. A solid sphere is rolling on a surface. What fraction of its total kinetic energy is in the form of rotational kinetic energy about the center of mass? Number Units
A cylinder of mass 12.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed of 11.0 m/s. (a) Determine the translational kinetic energy of its center of mass. (b) Determine the rotational kinetic energy about its center of mass. (c) Determine its total energy
A 11.9-kg cylinder rolls without slipping on a rough surface. At an instant when its center of gravity has a speed of 11.9 m/s, determine the following. (a) the translational kinetic energy of its center of gravity (b) the rotational kinetic energy about its center of gravity (c) its total kinetic energy Submit Answer
A cylinder of mass 6.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed of 7.0 m/s. (a) Determine the translational kinetic energy of its center of mass. J (b) Determine the rotational kinetic energy about its center of mass. J (c) Determine its total energy. J
Circle answers please A cylinder of mass 6.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed of 7.0 m/s. (a) Determine the translational kinetic energy of its center of mass. (b) Determine the rotational kinetic energy about its center of mass. (c) Determine its total energy.
Part 1: A DVD is initially at rest so that the line PQ on the disc's surface is along the +x-axis. The disc begins to turn with a constant α = 5.0 rad/s2. .1. At-0.40s, what is the angle between the line PQ and the +x-axis? A. 0.40 rad B. 0.80 rad C. 1.0 rad D. 2.0 rad 2. How do the centripetal acceleration and tangential acceleration compare at points P and Q?Part 2: 3. You want to double the radius of a rotating...
A cylinder of mass 11.0 kg and radius 0.260m rolls without slipping on a horizontal surface. At a particular instant, its center of mass has a speed of 7.30 m/s. Its rotational kinetic energy about its center of mass is then 147J. a) What is in kg m2 its moment of inertia about its center of mass? b) What is in J its linear kinetic energy at that instant? c) What is in J its total kinetic energy at that...