A planet of mass m=8.55×1024 kgm=8.55×1024 kg is orbiting in a circular path a star of...
A planet of mass m=8.55×1024 kgm=8.55×1024 kg is orbiting in a circular path a star of mass M=9.35×1029 kgM=9.35×1029 kg . The radius of the orbit is R=3.75×107 kmR=3.75×107 km .
What is the orbital period (in Earth days) of the planet TplanetTplanet ?
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A planet of mass
m=8.55×1024 kgm=8.55×1024 kg is orbiting in a circular path a star
of...
A planet of mass m=2.95×1024 kg is orbiting in a circular path a star of mass...
A planet of mass m=2.95×1024 kg is orbiting in a circular path a star of mass M=1.75×1029 kg . The radius of the orbit is R=6.25×107 km . What is the orbital period (in Earth days) of the planet Tplanet ?
A planet of mass m = 6.25 × 1024 kg is orbiting in a circular path...
A planet of mass m = 6.25 × 1024 kg is orbiting in a circular path a star of mass M = 7.85 × 1029 kg. The radius of the orbit is R = 5.65 × 107 km. What is the orbital period (in Earth days) of the planet Tplanet?
A planet of mass m = 7.85 × 1024 kg is orbiting in a circular path...
A planet of mass m = 7.85 × 1024 kg is orbiting in a circular path a star of mass M = 3.85 × 1029 kg. The radius of the orbit is R = 8.35 × 107 km. What is the orbital period (in Earth days) of the planet Tplanet?
A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path...
A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path a star of mass M = 9.75 x 1029 kg. The radius of the orbit is R = 4.65 x 107 km. What is the orbital period (in earth days) of the planet? Where G = 6.67 � 10-11 N�m2/kg2 and 1 day = 8.54 � 104 s. I used the formula and got T = 247 s = 0.0289 days, but the online...
A planet has a mass of 7.24 × 1024 kg and a radius of 7240 km....
A planet has a mass of 7.24 × 1024 kg and a radius of 7240 km. (a) Find the orbital radius of a satellite that is to complete 1 orbit every 3.4 hours. (b) Find the tangential velocity of a satellite that is to orbit 560 km above this planet’s surface. (c) Find the time period of a satellite that has an orbital radius of 9.35 × 107 m around this planet.
2. A new Earth-like planet is found orbiting a distant star with a circular orbit. The...
2. A new Earth-like planet is found orbiting a distant star with a circular orbit. The it takes 1.3 Earth years for the planet to make a full circle around it's star. The star has a radius 5 x 1011m. The altitude of the planet's orbit is 8 x 105 km. Find the mass of the star that the new planet is orbiting.
Astronomers discover an exoplanet, a planet orbiting a star other than the Sun, that has an...
Astronomers discover an exoplanet, a planet orbiting a star other than the Sun, that has an orbital period of 4.01 Earth years in a circular orbit around its star, which has a measured mass of 3.97X10^30. Find the radius of the exoplanet's orbit.
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular Ind the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G= 6.67x10-11 m3 kg-152) (In the choices below, 10^4 is 104)
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x...
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular and the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G=6.67x10-11 mº kg1s 2) (In the choices below, 10^4 is 104) O 2.99 x 10^4 m/s 8.92 x 10^4 m/s O 4.58 x 10^4 m/s O...
Planet X of mass mx = 6.3 × 1024 kg orbits S in uniform circular motion...
Planet X of mass mx = 6.3 × 1024 kg orbits
S in uniform circular motion at a distance rx and with a
period Px = 1.5 years (=4.7304 × 107 s). The
mass of the star S is MS = 2 × 1031
kg and its radius is RS = 4.2 × 108 m, as
shown in the figure.
1) What is rx, the orbital radius of Planet X around
the Sun?
a) rx = 4.21 × 109 m...
2. A new Earth-like planet is found orbiting a distant star with a circular orbit. The it takes 1.3 Earth years for the planet to make a full circle around it's star. The star has a radius 5 x 1011m. The altitude of the planet's orbit is 8 x 105 km. Find the mass of the star that the new planet is orbiting.
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular Ind the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G= 6.67x10-11 m3 kg-152) (In the choices below, 10^4 is 104)
A planet of mass 5.97 x 1024 kg revolves around a star of mass 2 x 1030 kg. Consider the orbit of the planet to be circular and the star is at the center. The distance between the star and the planet is 1.496 x 1011 m. Calculate the orbital velocity of the planet. (G=6.67x10-11 mº kg1s 2) (In the choices below, 10^4 is 104) O 2.99 x 10^4 m/s 8.92 x 10^4 m/s O 4.58 x 10^4 m/s O...
Planet X of mass mx = 6.3 × 1024 kg orbits
S in uniform circular motion at a distance rx and with a
period Px = 1.5 years (=4.7304 × 107 s). The
mass of the star S is MS = 2 × 1031
kg and its radius is RS = 4.2 × 108 m, as
shown in the figure.
1) What is rx, the orbital radius of Planet X around
the Sun?
a) rx = 4.21 × 109 m...
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