Question

C++

Write a function so that the main() code below can be replaced by the simpler code that calls function MphAndMinutesToMiles(). Original main():

int main() {
   double milesPerHour;
   double minutesTraveled;
   double hoursTraveled;
   double milesTraveled;

   cin >> milesPerHour;
   cin >> minutesTraveled;

   hoursTraveled = minutesTraveled / 60.0;
   milesTraveled = hoursTraveled * milesPerHour;

   cout << "Miles: " << milesTraveled << endl;

   return 0;
}

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#include <iostream>

using namespace std;

/* Your solution goes here */

int main() {

double milesPerHour;

double minutesTraveled;

cin >> milesPerHour;

cin >> minutesTraveled;

cout << "Miles: " << MphAndMinutesToMiles(milesPerHour, minutesTraveled) << endl;

return 0;

}

#include <iostream>
using namespace std;

/* Your solution goes here */

int main() {
double milesPerHour;
double minutesTraveled;

cin >> milesPerHour;
cin >> minutesTraveled;

cout << "Miles: " << MphAndMinutesToMiles(milesPerHour, minutesTraveled) << endl;

return 0;
}

Answer 1

#include <iostream>
using namespace std;

double MphAndMinutesToMiles(double milesPerHour, double minutesTraveled){
    double hoursTraveled;
    double milesTraveled;
    hoursTraveled = minutesTraveled / 60.0;
    milesTraveled = hoursTraveled * milesPerHour;
    return milesTraveled;
}

int main() {
double milesPerHour;
double minutesTraveled;

cin >> milesPerHour;
cin >> minutesTraveled;

cout << "Miles: " << MphAndMinutesToMiles(milesPerHour, minutesTraveled) << endl;

return 0;
}