If I have an initial concentration of NaOH of 1.25M in 15mL, and add 10mL water...
If I have an initial concentration of NaOH of 1.25M in 15mL, and add 10mL water to get a final concentration of 25mL, what's the final concentration of the NaOH?
I did C1V1 = C2V2 and got 0.5M
Is that correct?
Homework Answers
Here, C1 = 1.25 M , C2 = 0 M, V1 = 15 mL, V2 = 10 mL.
Then volume of mixture formed is:
Vmix = 15 + 10 = 25 mL
Calculate the concentration of the mixture formed as follows:
CmixVmix = C1V1 + C2V2
Cmix*25 = 1.25*15 + 0*10
Cmix = (1.25*3)/5 = 0.25*3 = 0.75 M
Therefore, the concentration of mixture formed is 0.75 M. Answer is 0.75 M.
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