A solution contains naphthalene (C10H8) dissolved in hexane (C6H14) at a concentration of 11.17 % naphthalene by mass.
Calculate the vapor pressure at 25 ∘C of hexane above the solution. The vapor pressure of pure hexane at 25 ∘C is 151 torr.
Express the answer using three significant figures.
Mass of naphthalene,m1 = 11.17 g
Molar mass of naphthalene,M1 = 128.17052 g/mol
Moles of napthalene,n1
n1 = m1/M1
n1= ((11.17 g) / (128.17052 g/mol))
n1 = 0.0866 moles
Mass of hexane,m2 = 88.83 g
Molar mass of hexane,M2 = 86.18 g/mol
Moles of hexane,n2
n2 = ((88.83 g )/(86.18 g/mol))
n2 = 1.03 moles
Mole fraction hexane = (1.03 / (1.03 + 0.0866))= 0.922
Vapor pressure of hexane = Pure vapor pressure x mole fraction
Vapor pressure of hexane = 0.922×151 = 139 torr
A solution contains naphthalene (C10H8) dissolved in hexane (C6H14) at a concentration of 11.17 % naphthalene...
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