Concentrated hydrochloric acid (HCl) (molecular mass 36.5 g/mol) has a molarity of 3.6M.
What volume of concentrated HCl would you need to add to prepare a 20% (w/v) solution of HCl with a final volume of 500 mL,
I have calcualted that 3.6mol/L x 36.5g/mol =131.40g/L.
Then to get the 100ml value and percentage: 131.40/1000 x 100 =13.14g/100ml therefore 13.14%. 20% of this would be 2.628g. Is this the answer?
Concentrated hydrochloric acid (HCl) (molecular mass 36.5 g/mol) has a molarity of 3.6M. What volume of...
Concentrated hydrochloric acid is 38% HCl by weight and has a density of 1.19 g/mL. A solution is prepared by measuring 67 mL of the concentrated HCl, adding it to water, and diluting to 0.800 L. Calculate the approximate molarity of this solution from the volume, percent composition, and density.
Concentrated hydrochloric acid is 38% HCl by weight and has a density of 1.19 g/mL. A solution is prepared by measuring 36 mL of the concentrated HCI, adding it to water, and diluting to 0.500 L. Calculate the approximate molarity of this solution from the volume, percent composition, and density. Answer:
Hydrochloric acid is usually purchased in a concentrated form that is 37.0% HCl by mass and has a density of 1.20 g/mL. How much concentrated solution would you take to prepare 3.05 L of 0.545 M HCl by mixing with water?
A certain supply of concentrated hydrochloric acid has a concentration of 36.0% HCl in water solution. The density of the solution is 1.19 g/mL. Calculate the molarity of HCl in the solution.
According to the label on a bottle of concentrated hydrochloric acid, the contents are 36.0% HCl by mass and have a density of 1.18 g/mL. What volume of it would you need to prepare 401 mL of 2.60 M HCl?
When preparing the following solutions, indicate each concentration by mass percentage (%), mass to volume percentage (w/v%) and molar concentration (M). WWW (1) Preparation of diluted ammonia water: Add pure water to 400 mL of strong ammonia water (28%, specific weight: 0.9, molecular weight: 17.0) to make 1000 mL. (2) Preparation of dilute hydrochloric acid: Add pure water to 23.6 mL of hydrochloric acid (36.5%, specific weight: 1.18, molecular weight: 36.5) to make 100 mL. (3) Dilute nitric acid: Add...
What is the molarity of the hydrochloric acid if 37.55 mL of HCl is required to neutralize 1.130 g of sodium hydrogen carbonate? HCl(aq)+NaHCO3(aq)→NaCl(aq)+H2O(l)+CO2(g)
What is the molarity of the hydrochloric acid if 38.85 mL of HCl is required to neutralize 1.015 g of sodium hydrogen carbonate? HCl(aq)+NaHCO3(aq)→NaCl(aq)+H2O(l)+CO2(g)
molarity of acid: 0.1435M
volume:25ml
1. Use the molar mass and moles of acetic acid to determine the mass of the acetic acid in the 25.00-ml sample. 2. Calculate the mass/volume percentage (m/v %) by dividing the mass of acetic acid in grams by the volume of the vinegar sample in mL and multiplying by 100. 3. For the reaction of sodium hydroxide solution with a solution of hydrochloric acid: a. Write a balanced molecular equation for the reaction, including...
3 pts Question 13 What is the molarity of an aqueous solution of hydrochloric acid if 50.00 mL of 5.00 M HCl(aq) is diluted to a new volume of 100.0 mL? 5.00M 100M 2.50M 1.25M 3 pts Question 14 How many moles of sulfuric acid are in 300.0 mL of 2.00 M H2SO4(aq) 300 mol 0.300 ml 500 ml 0.600 mol