Question

C++ question. Please help, thank you!

Write a function called averageOdd that returns the average of all of the odd numbers in a 2-Dimensional array with 3 columns. If no odd numbers are present, it should return a result of 0. Excessively long solutions that use more than 15 lines of code may lose points. For example, a program that uses the function averageOdd follows:

int main() {

int data[2][3] = {{3, 1, 4} , {2, 7, 1}};

cout << averageOdd(data, 2, 3) << endl;  

// prints 3.0

// because the odd entries 3, 1, 7, 1 average to 3.0

return 0;

}

Answer 1

#include <iostream>
using namespace std;

double averageOdd(int arr[][3], int r, int c){
   double sum = 0;
   int count = 0;
   for(int i=0;i<r;i++){
      for(int j = 0;j<c;j++){
         if(arr[i][j]%2==1){
            sum += arr[i][j];
            count += 1;
         }
      }
   }
   if(count == 0){
      return sum;
   }
   else{
      return sum / count;
   }
}

int main() {

int data[2][3] = {{3, 1, 4} , {2, 7, 1}};

cout << averageOdd(data, 2, 3) << endl;  

// prints 3.0

// because the odd entries 3, 1, 7, 1 average to 3.0

return 0;

}