Question

The reactions in the table are all zero order and follow the same general reaction process...

The reactions in the table are all zero order and follow the same general reaction process of A→products. Half‑life, t1/2 (s) Rate constant, k (M⋅s−1) Initial concentration, [A]0 (M) Reaction 1 5.31 0.0731 ? Reaction 2 ? 0.0391 0.571 Reaction 3 5.91 ? 0.491 Reaction 4 3.31 0.0371 ? Reaction 5 6.31 ? 0.351 Calculate the missing values for half‑life (t1/2 ), rate constant (k), and initial concentration, [A]0. reaction 1 initial concentration, [A]0: M reaction 2 half‑life, t1/2: s reaction 3 rate constant, k: M⋅s−1 reaction 4 initial concentration, [A]0: M reaction 5 rate constant, k: M⋅s−1

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
The reactions in the table are all zero order and follow the same general reaction process...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The reactions in the table are all zero order and follow the same general reaction process...

    The reactions in the table are all zero order and follow the same general reaction process of A → products. Half-life, 112 (8) Rate constant, * (M.5-) Initial concentration, [A]. (M) Reaction 1 3.71 0.0731 ? Reaction 2 0.0671 0.971 Reaction 3 5.11 ? 0.411 Reaction 4 4.31 0.0771 ? Reaction 5 4.31 0.371 ? ? Calculate the missing values for half-life (fin), rate constant (k), and initial concentration, (Alo. reaction 1 initial concentration, (Alo: M action 2 half-life, 112...

  • The reactions in the table are all zero order and follow the same general reaction process of A → products

    The reactions in the table are all zero order and follow the same general reaction process of A → productsCalculate the missing values for half-life (t1/2), rate constant (k), and initial concentration. [A]0. 

  • For a first-order reaction, the half-life is constant. It depends only on the rate constant k...

    For a first-order reaction, the half-life is constant. It depends only on the rate constant k k and not on the reactant concentration. It is expressed as t1/2=0.693k t 1 / 2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0. A certain first-order reaction (A→products A → p r o d u c t s ) has a rate constant of 9.30×10−3...

  • Half-life equation for first-order reactions: t1/2=0.693k   where t1/2 is the half-life in seconds (s), and k...

    Half-life equation for first-order reactions: t1/2=0.693k   where t1/2 is the half-life in seconds (s), and k is the rate constant in inverse seconds (s−1). a) What is the half-life of a first-order reaction with a rate constant of 4.80×10−4  s−1? b) What is the rate constant of a first-order reaction that takes 188 seconds for the reactant concentration to drop to half of its initial value? Express your answer with the appropriate units. c)A certain first-order reaction has a rate constant...

  • please help explain this to me step by step, thank you so much! A reactant decomposes...

    please help explain this to me step by step, thank you so much! A reactant decomposes with a half-life of 15.7 s when its initial concentration is 0.491 M. When the initial concentration is 2.67 M, this same reactant decomposes with a half-life of 85.5 s. What is the order of the reaction? What is the value and unit of the rate constant for this reaction? Unit: 0 M-s-1 k=11 4.4 ×10

  • The half-life of a reaction, t1/2, is the time it takes for the reactant concentration [A]...

    The half-life of a reaction, t1/2, is the time it takes for the reactant concentration [A] to decrease by half. For example, after one half-life the concentration falls from the initial concentration [A]0 to [A]0/2, after a second half-life to [A]0/4, after a third half-life to [A]0/8, and so on. on. For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t1/2=0.693k For a...

  • + Half-life for First and Second Order Reactions 11 of 11 The half-life of a reaction,...

    + Half-life for First and Second Order Reactions 11 of 11 The half-life of a reaction, t1/2, is the time it takes for the reactant concentration A to decrease by half. For example, after one half-Me the concentration falls from the initial concentration (Alo to A\o/2, after a second half-life to Alo/4 after a third half-life to A./8, and so on. on Review Constants Periodic Table 11/25 For a second-order reaction, the half-life depends on the rate constant and the...

  • For a first-order reaction, the half-life is constant. It depends only on the rate constant k...

    For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t 1/2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t 1/2 = 1 k[A ] 0 Part A A certain first-order reaction ( A→products ) has a rate constant of 9.90×10−3 s −1 at 45 ∘...

  • An enzyme catalyzes conversion of sucrose to fructose. The half-life of the reaction depends on the...

    An enzyme catalyzes conversion of sucrose to fructose. The half-life of the reaction depends on the concentration of sucrose. With an initial concentration of 3.0 M sucrose, t1/2 = 1.36x10–4 s. With an initial concentration of 1.0 M sucrose, t1/2 = 4.5x10–5 s. a. What is the reaction order in sucrose? b. Calculate the rate constant for the reaction.

  • 1. Initial‑rate data at a certain temperature is given in the table for the reaction N2O3(g)⟶NO(g)+NO2(g)...

    1. Initial‑rate data at a certain temperature is given in the table for the reaction N2O3(g)⟶NO(g)+NO2(g) [N2O3]0(M) Initial rate (M/s) 0.100 0.510 0.200 1.020 0.300 1.530 Determine the value and units of the rate constant. k= units: 2. Using the data in the table, determine the rate constant of the reaction and select the appropriate units. A+2B⟶C+D Trial [A] (M)[A] (M) [B] (M)[B] (M) Rate (M/s) 1 0.340 0.340 0.0127 2 0.340 0.680 0.0127 3 0.680 0.340 0.0508 k= Units...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT