We rotate a disk by wrapping it with a string, and letting a falling mass apply a torque. If you hang a 500g mass from the string, and it drops 0.7m in 0.7s, what is its acceleration?
We rotate a disk by wrapping it with a string, and letting a falling mass apply...
A string is wound around a disk of mass M = 215 kg and a radius of R = 0.310 m. The disk is free to rotate about its center by a frictionless pin. The other end of the string is attached to a mass m = 87.0 kg. The mass is released from rest and travels downward causing the cylinder to rotate. How many revolutions did the disk make 6 seconds after the release of mass m from rest?
A mass of 5kg starts from rest and pulls down vertically on a string wound around a disk-shaped, massive pulley. The mass of the disk is 5kg and its radius is 2 m. What is the linear speed, in m/s, after the mass drops by 0.3 m? What's the concept here? Kinetic Energy of Rotation or are we supposed to use Torque? If someone can help me with the concept and give me steps on how to solve this, it...
A uniform disk of radius 0.455 m0.455 m and unknown mass is constrained to rotate about a perpendicular axis through its center. A ring with the same mass as the disk is attached around the disk's rim. A tangential force of 0.237 N0.237 N applied at the rim causes an angular acceleration of 0.129 rad/s2.0.129 rad/s2. Find the mass of the disk.Why is this wrong? A uniform disk of radius 0.455 m and unknown mass is constrained to rotate about...
A uniform disk of radius 0.461 m and unknown mass is constrained to rotate about a perpendicular axis through its center. A ring with the same mass as the disk is attached around the disk's rim. A tangential force of 0.243 N applied at the rim causes an angular acceleration of 0.123 rad/s2. Find the mass of the disk. mass of disk:
A uniform disk of radius 0.551 m and unknown mass is constrained to rotate about a perpendicular axis through its center. A ring with same mass as the disk\'s is attached around the disk\'s rim. A tangential force of 0.229 N applied at the rim causes an angular acceleration of 0.103 rad/s2. Find the mass of the disk.
A solid disk with mass M (1.00 kg) and radius R (0.200 m) is sitting on a frictionless surface. We analyzed the situation at left below, where a force F (2.00 N) is applied for four seconds, by a string that has been wrapped around the outer surface of a cylindrical disk. Two students are debating the following question. ‘The same force is applied for the same amount of time, but this time by a string attached to the edge...
A certain pulley is a uniform disk of mass 2.7 kg and radius 0.25 m. A rope applies a constant torque to the pulley, which is free to rotate without friction, resulting in an angular acceleration of 0.12 rad/s2. The pulley starts at rest at time t = 0 s. What is its rotational kinetic energy at t = 2.2 s?
the question is in last picture. i provided the lab content... I need guidance. thank you. INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...
A uniform solld disk of radius R and mass M is free to rotate on a frictionless plvot through a point on its rim (see figure below). The disk is released from rest In the position shown by the Pivot (a) What is the speed of its center of mass when the disk reaches the position indicated by the dashed circle? (Use any variable or symbol stated above along with the following as necessary: g) (b) What is the speed...
6) A uniform 1kg disk with a radius of 1 m has a disk drilled out creating a thick walled ring. A torque of 2Nmis applied causing the thick walled ring to rotate about its center . If the angular is acceleration of 6.4 rads/s^2, what is the radius of the hole placed in the center . Assume a uniform mass per area.