H0 : µ =21.7 verses HA : µ < 21.7 Rejection Region: t <−t89,0.05 =−1.662 t...
H0 : µ =21.7 verses HA : µ < 21.7 Rejection Region: t <−t89,0.05 =−1.662 t =−1.798 <−t89,0.05 =−1.662 Reject H0 at α =5%. The data show sufficient evidence that the average number of Type 2 fibers is less than 21.7
what is the p-value?
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H0 : µ =21.7 verses HA : µ < 21.7 Rejection Region: t
<−t89,0.05 =−1.662 t...
The five parts are: i. Null Hypothesis: H0 : µ =5.2 ii. Alternative Hypothesis: HA :...
The five parts are: i. Null Hypothesis: H0 : µ =5.2 ii. Alternative Hypothesis: HA : µ < 5.2 iii. Rejection Region: Reject H0 if t statistic <−t49,.05 =−1.677 iv. Test Statistics: t = Y−µ0 S/pn = 5−5.2 0.7/p50 =−2.0203 <−t49,.05 =−1.677 v. Conclusion. Reject H0 at α = 5%. The data support that the mean dissolved oxygen count of the water is less than the reading at this location over the past year. What is the p-value?
In a single sample t-test with H0: µ = 25 against HA: µ 25, a...
In a single sample t-test with H0: µ = 25 against HA: µ 25, a sample of size 10 produced a sample mean of 26 and a computed t-value of 2.182. At the 0.05 level of significance, this means: A. there is sufficient evidence to conclude that µ not equal to 25 B. there is sufficient evidence to conclude that µ = 25 C. there is sufficient evidence to conclude that µ = 26 D. there is sufficient evidence...
Suppose you want to test H0 : µ = 4 against Ha : µ > 4....
Suppose you want to test H0 : µ = 4 against Ha : µ > 4. In addition, suppose that σ = 5, n = 36, and you will reject H0 if x > 5 and accept H0 otherwise. (a) (6 pts) Find the power of this test against the alternative µ = 5.6. (b) (2 pts) Find the probability of a Type II error in this situation (just use your answer from part (a) to help you do this).
Consider the following hypothesis test. H0: μ ≤ 12 Ha: μ > 12 A sample of...
Consider the following hypothesis test. H0: μ ≤ 12 Ha: μ > 12 A sample of 25 provided a sample mean x = 14 and a sample standard deviation s = 4.28. (a) Compute the value of the test statistic. (Round your answer to three decimal places.) (b) Use the t distribution table to compute a range for the p-value. p-value > 0.2000.100 < p-value < 0.200 0.050 < p-value < 0.1000.025 < p-value < 0.0500.010 < p-value < 0.025p-value <...
For the following cases, you may use either the P-value approach or the rejection region approach...
For the following cases, you may use either the P-value approach or the rejection region approach to present a full hypothesis test, including: Identifying the claim and H0 and Ha, Finding the appropriate standardized test statistic, Finding the P-value or the rejection region, Deciding whether to reject or fail to reject the null hypothesis, and Interpreting the decision in the context of the original claim. A city planner claims that the mean speed of westbound traffic along a road segment...
QUESTION 1: You are testing H0: µ = 100 against Ha: µ < 100 based on...
QUESTION 1: You are testing H0: µ = 100 against Ha: µ < 100 based on an SRS of 18 observations from a Normal population. The data give x¯¯¯x¯ = 8.3 and s = 5. The value of the t statistic (±0.01) is QUESTION 2: You have an SRS of 14 observations from a Normally distributed population. What critical value (±±0.001) would you use to obtain a 99.5% confidence interval for the mean μμ of the population?
Identify the null and alternative hypothesis and find the critical t-value(s), t0, and the rejection region(s)...
Identify the null and alternative hypothesis and find the critical t-value(s), t0, and the rejection region(s) for a t-test to test the claim that μ1 ≠ μ2. Assume that the variance is equal between the populations and use α = 0.10. Assume n1 = 50 and n2 = 45. H0: Ha: T0 = Rejection Region =
Consider the following hypotheses: H0: μ = 19 HA: μ ≠ 19 The population is normally...
Consider the following hypotheses: H0: μ = 19 HA: μ ≠ 19 The population is normally distributed. A sample produces the following observations: (You may find it useful to reference the appropriate table: z table or t table) 20 23 17 21 21 24 23 Click here for the Excel Data File a. Find the mean and the standard deviation. (Round your answers to 2 decimal places.) b. Calculate the value of the test statistic. (Round intermediate calculations to...
In testing H0: µ = 3 versus Ha: µ ¹ 3 when =3.5, s = 2.5,...
In testing H0: µ = 3 versus Ha: µ ¹ 3 when =3.5, s = 2.5, and n = 100, what is the p-value? a.0.0700 b.0.0228 c.0.0655 d.0.0456
Consider the following hypothesis test: H0: μ = 18 Ha: μ ≠ 18 A sample of...
Consider the following hypothesis test: H0: μ = 18 Ha: μ ≠ 18 A sample of 48 provided a sample mean x = 17 and a sample standard deviation s = 4.9. a. Compute the value of the test statistic (to three decimal places.) b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value. (to two decimal places) p-value is between is c. At α = .05, what is your conclusion? p-value...
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