A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t=0 the puck is moving to the right at 3.02 m/s .
Part A)
Calculate the magnitude of the velocity of the puck after a force of 25.4 N directed to the right has been applied for 6.0×10−2 s .
V= m/s
given
m = 0.16 kg
vi = 3.02 m/s
A) F = 25.4 N
delta_t = 6*10^-2 s
vf = ?
use Impulse-momentum theorem
Impulse = change in momentum
F*delta_t = m*(vf - vi)
vf - vi = F*delta_t/m
vf = vi + F*delta_t/m
= 3.02 + 25.4*6*10^-2/0.16
= 12.5 m/s <<<<<<<<-----------------------Answer
A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t=0 the puck...
A 0.160-kg hockey puck is moving on an icy, frictionless, horizontal surface. At t=0 the puck is moving to the right at 3.02 m/s . part A) Calculate the magnitude of the velocity of the puck after a force of 25.4 N directed to the right has been applied for 6.0×10−2 s V= m/s
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