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A chest x-ray calls for 100 kVp kVp, 9 mAs, which results in an x-ray intensity...

A chest x-ray calls for 100 kVp kVp, 9 mAs, which results in an x-ray intensity of 359 μGy measured at the patient's location. If the mAs is increased to 17 mAs, what will the new x-ray intensity be? Give your answer to the nearest μGy

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Answer #1

(intensity is directly proportional to current squared)

k is Constant and I is the current

Intensity2 = 1281μGy

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