a ball is kicked off the ground with a speed of 10m/s at an angel of 30* above horizontal. it lands on 3m net. find kinematic info
xi,yi
xf, yf
vix viy
vfx vif
ax ay
t
It lands on 3 m net ?????
is it the height at which the ball lands ????
If yes,
then
yf = 3 m
yi = 0 m ( launched from ground)
xi = 0 m
xf =
vix = 10 * cos 30 = 8.66 m/s
viy = 10 * sin 30 = 5 m/s
ax = 0 m/s2
ay = - 9.8 m/s2
vfx = 8.66 m/s (horizontal speed does not change at any time)
Now, to find time t,
yf = yi + vyt - 1/2gt2
3 = 0 + 5t - 4.9t2
we get a quadratic equation
Now, here comes the problem, as you can see this quadratic equation cannot be solved ....that's why please check you question again....is it 3 m final height or 3 m horizontal distance ??
4.9t2 - 5t + 3 = 0
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