Balance the following redox reactions:
a) CN− + MnO4− → CNO− + MnO2 (basic solution)
b) O2 + As → HAsO2 + H2O (acidic solution)
c) Br− + MnO4− → MnO2 + BrO3− (basic solution)
d) NO2 → NO3− + NO (acidic
solution)
e) ClO4− + Cl− → ClO− +
Cl2 (acidic solution)
f) AlH4− + H2CO → Al3+ + CH3OH (basic solution)
Balance the following redox reactions: a) CN− + MnO4− → CNO− + MnO2 (basic solution) b)...
Balance the redox reactions: basic: ClO-(aq)+Cr(OH)4-(aq)----> CrO42-(aq)+Cl-(aq) MnO4-(aq)+Br-(aq)--> MnO2(s)+BrO3-(aq) NO2-(aq)+Al(s)--->NH3(g)+AlO2- Aidic: ClO4-(aq)+Cr(OH)4---->ClO3-(aq)+Cl2(g)
Balance the redox equations: a. CO2+ Mn2+→H2C2O4+ MnO4- (in basic conditions) b. Br- + MnO4 ----> MnO2+ BrO3- (in acidic conditions) Please show all steps and explain
Balance Redox Equations (Basic Solution) with steps. 1. Mn^2+ (aq) + Br2(l) = MnO2 (s) + Br^- (aq) 2. NO2^- (aq) + MnO4^- (aq) = NO3^- (aq) + MnO2 (s) 3. N2H4 (g) + ClO3^- (aq) = NO(g) + Cl^- (aq)
Balancing Oxidation–Reduction Reactions (Section)Complete and balance the following equations, and identify the oxidizing and reducing agents:(a) Cr2O72-(aq) + I-(aq)→Cr3+(aq) + IO3-(aq) (acidic solution)(b) MnO4-(aq) + CH3OH(aq) →Mn2+(aq) +HCO2H(aq) (acidic solution)(c) I2(s) + OCl-(aq)→IO3-(aq) + Cl-(aq) (acidic solution)(d) As2O3(s) + NO3-(aq)→H3AsO4(aq) + N2O3(aq) (acidic solution)(e) MnO4-(aq) + Br-(aq)→MnO2(s) + BrO3-(aq) (basic solution)(f) Pb(OH)42-(aq) + ClO-(aq)→PbO2(s) + Cl-(aq) (basic solution)
Complete and balance the following redox reaction in basic solution MnO4-(aq) + Br-(aq) → MnO2(s) + BrO3-(aq) Attempts remaining: 3 Complete and balance the following redox reaction in basic solution 103-(aq) + Re(s) → Re04 (aq) + 10-(aq) Attempts remaining: 3
Balance the following Redox Equations in Basic Mediums. Redox Reactions in Basic Solution 1. Al(s) + MnO4¯ (aq) ¾® MnO2(s) + Al(OH)4¯ (aq) 2. NO2¯ (aq) + Al(s) ¾® NH3(aq) + AlO2¯ (aq) 3. Cr(s) + CrO42-(aq) ¾® Cr(OH)3(s) Note: Cr(OH)3 is found in BOTH half reactions! 4. Cl2(aq) + Br2(l) ¾® OBr¯ (aq) + Cl¯ (aq) 5. S8(aq) + MnO4¯ (aq) ¾® SO42-(aq) + MnO2(s)
Balance the following redox equations by the ion-electron method: (a) H2O2 + Fe2+ → Fe3+ + H2O (in acidic solution) (b) Cu + HNO3 → Cu2+ + NO + H2O (in acidic solution) (c) CN− + MnO4− → CNO− + MnO2 (in basic solution)
Balance the equation for redox reaction in basic solution a) MnO2 (s) + ClO3 - MnO4- + Cl- b) ClO2 ClO3- + Cl-
Balance the following redox reactions by balancing the half reactions and then combine the half reactions to get the overall balanced redox reaction with the lowest possible whole number coefficients. 1. Consider the following unbalanced redox reaction: MnO2(s) + BrO3−(aq) → MnO4−(aq) + Br−(aq) (a) Balance the corresponding half reactions in acidic conditions using the lowest possible whole number coefficients. (Enter coefficients for one and zero. Blanks will be marked incorrect.) MnO2(s) + H2O(l) + OH−(aq) + H+(aq) + e− → MnO4−(aq) + H2O(l) + OH−(aq) + H+(aq)...
Balance the following redox equations by the half-reaction method: (a) Mn2+ + H2O2 → MnO2 + H2O (in basic solution) (b) Bi(OH)3 + SnO22− → SnO32− + Bi (in basic solution) (c) Cr2O72− + C2O42− → Cr3+ + CO2 (in acidic solution) (d) ClO3− + Cl− → Cl2 + ClO2 (in acidic solution) (e) Mn2+ + BiO3− → Bi3+ + MnO4− (in acidic solution)