Balance the equation
KBrO3(s)------->KBr(s)+O2(g)
In balanced chemical reaction, atoms in either side of reaction are same.
KBrO3 (s) KBr(s) + O2 (g)
Balancing O we have:
2KBrO3 (s) KBr(s) + 3O2 (g)
Balancing other atoms, we have:
2KBrO3 (s) 2KBr(s) + 3O2 (g)
The standard entropies, So, are given below for some substances at 25°C. KBrO3 (s); So =149.2 J/Kmol KBr (s); So =96.4 J/Kmol O2 (g); So =205.0 J/Kmol Calculate So for this reaction: KBrO3 (s) → KBr (s) + 3/2 O2 (g)
1.- Calculate the % yield when you react 20mg of KBrO3 and produce 5 mg of KBr, assume all other reagents are in excess. Balance the equation, Indicate the reactants and the products. (KBrO: Molecular mass: 166.999 g/mol, KBr Molecular mass: 119.002 g/mol) KBrO; + KI + HBr → KBr + H2O a) If you start the reaction with 20mg of KBro; and 20mg of Kl (molecular mass=166.0028 g/mol) with an excess of HBr what is the limiting reagent? b)...
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