Hi! I need help with a practice problem. Im not quite sure how to solve it. Thank you in advance!
Let f(n) = log3n + 1. Prove f(n) is O(log19n). Hint: Use the change of base formula for logs.
log19(n) = log3(n) / log3(19)
=> log3(n) = 2.68 * log19(n)
Hence, for c = 3.68 and n = 0, we have
0 <= log3n + 1 <= 3.68 * log19(n)
Hence, f(n) = O(log19 n)
Hi! I need help with a practice problem. Im not quite sure how to solve it....
Hi I need some help with this problem and make sure do not copy any other problems because I need to have how you did the solution please provide clear format so I can understand how you get the answer. Thank you. Compute
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