Question

Hi I need some help with this problem and make sure do not copy any other problems because I need to have how you did the solution please provide clear format so I can understand how you get the answer. Thank you.

1. Compute

Answer 1

sio 18 1] A' mod 26 = ? . 14 .7 22/3x3 m First find the co-factor moet zix . ie - [+ [Dixi -+r3] - [17x21 - ux3] + [17x7«ux]]] - [18x21 -7*1] + [lox 21 –ux 1] - [10x9-1974] [+ [3x18-1X1] - [10x3 - 1981] + [10x) - 17x18] ſo -345 1157 Co factor (A) = -371 206 2 L 53 -13 -296 and determinans of matrix A is. STAI = 10 T 31 117 31 S 17 2114 2114 i =10 (21-21)-18119821–4x3) +1 (1787–49)) -0-18 x 34 5 +115 thone . TAJ = - 6095 = -6095 mod 26 ! Now, -,6095 = 23 5 remainder 15 26 otherwise, - 6095 3234 remainder -|| ECS Scanned with CamScanner 26.

so -6095 mod 26 = 15 means 141= 15 h is not By taking 10 -371.539 Transpose of A mod-26 1 i Confactor 21-345 206 -13 Matrix LA) til for at least [115 ? -296).. = (15)' mod 26 po. -371 53.7. 1-345 20.6 -13 Llis 2 -296) 15-1 mod 26 = 15.2 = 26.4 + 15 mundifles 15, 30, 45, 60, 75, 90, 105=.. fi - Vaista 26. multiples · 26,52,78,104 -.-- By observations - 15,7 26.4+1 Scanned with CamScanner 105 = 104+1=105 L

so, x=7 » Invesse of 15. is 7 4 6 -9s97 37 7 | | 0 +/-345 2 -37 3 1 206 -13 = 1115 2 -2415 1 805 -296 1442 -91. 14 - 2072 Here again, -2597 mod 26=3 -2597 = 100 % 26 remainder 3 371 mod 26= 7 391 o'=14 rem.7 26 -2415 mod 26 - 3 -2415 2015 93 rem. 3 26 1442 mod 26:12 -91 mod 26 = 13 1442 .-55 ram. 12 26 2-4 rem, 63 805 mod 26 - 25 805 -30 rem, 25 26 -2072 mod 26-8 -2072 - 26 80 rene 8 A po 3 77 : 13 12 13 [25 14 8] Answer Answer Scanned with CamScanner