In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 135 above the water. If the briefcase hits the water 6.3 later, what was the speed at which the helicopter was ascending?
By using equation of motion,
s = ut + (1/2)at^2
Where, u is the initial velocity = v
t is time taken = 6.3 s
a acceleration due to gravity = - 9.8 m/s^2
s displacement = - 135 m
- 135 = v*6.3 + (1/2)*(-9.8)*(6.3)^2
v = (-135 + (1/2)*9.8*(6.3)^2) /6.3
= - 9.44 m/s
v = 9.44 m/s
In an action movie, the villain is rescued from the ocean by grabbing onto the ladder...