A car is travelling at constant speed of 60m/s on a highway. Another car needed to...
A car is travelling at constant speed of 60m/s on a highway. Another car needed to refuel so starting from rest, it leaves the area with an acceleration of 7m/2. It takes 3s for this car to enter the highway. This car keeps its acceleration constant on the highway. How long does it take for the entering car to catch the one that is travelling at 60m/s?
Homework Answers
Distance travelled by the car at Constant speed
X1=VT =60T
Speed of the second car after t=3 s ,from
V=Vo+at
V=0+7*3 =21 m/s-----------------1
The Distance traveled by second car in "T" seconds
X2=Vot+(1/2)at2
X2 = 21t+(1/2)(7)t2
X2 = 21T+3.5T2-----------------2
Therefore
X1=X2
60T = 21T+3.5T2
3.5T =39
T=11.143 s
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