In a 51.0 -g aqueous solution of methanol, CH 4 O , the mole fraction of methanol is 0.260. What is the mass of each component?
Total mass of aqueous solution of methanol = 51.0 g
Let the mass of methanol be x g.
Hence, mass of water = (51.0 - x) g.
Given that the mole fraction of methanol , 0.260
Molar mass of water = 18.01 g/mol
Hence, number of moles of water in the mixture is
Molar mass of methanol = 32.04 g/mol
Hence, number of moles of methanol in the solution is
Now, we can write the equation for the mole fraction of methanol as follows:
Hence, the amount of methanol in the solution is x= 19.6 g approximately.
Hence, the amount of water can be calculated as
Hence, there the mass of methanol component is 19.6 g and mass of water component is 31.4 g approximately.
Verification:
Moles of water =
Moles of methanol =
Hence, mole fraction of methanol is
Hence, our answer is correct.
In a 51.0 -g aqueous solution of methanol, CH 4 O , the mole fraction of...
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