ZuoTi.Pro
Question

The volume of water needed to dissolve 0.0541 grams of lead sulfate is  L. Assume no volume...

The volume of water needed to dissolve 0.0541 grams of lead sulfate is  L.

Assume no volume change upon addition of the solid.

B.The mass of iron(III) sulfide that is dissolved in 250 mL of a saturated solution is_____ grams.

C.A student measures the Cl- concentration in a saturated aqueous solution of lead chloride to be 3.32×10-2 M.
Based on her data, the solubility product constant for lead chloride is

Please Help!!!

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

I have provided the solution of problem A and C. In problem B neither normality nor molarity of solution is provided.

If molarity is provided, you can use formula molarity =weight /molecular wt. *volume in leter

I hope it helps you, please give me a positive feedback ?

0 0
Add a comment
Know the answer?
Add Answer to:
The volume of water needed to dissolve 0.0541 grams of lead sulfate is  L. Assume no volume...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT