What is the height H above the earth's surface at which all geosynchronous satellites (regardless of
mass) must be placed in orbit?
Note: A satellite that goes around the earth once every 24 hours is called a geosynchronous satellite.
Mass of Earth: 6*1024 kg, radius of Earth = 6400 km.
Note that the distance of the satellite from the Earth (r) in the formula is the distance from the center
of the Earth. When you find the total distance r, subtract radius of Earth from it to find the height
above the ground.
What is the height H above the earth's surface at which all geosynchronous satellites (regardless of...
Many satellites orbit Earth at maximum altitudes above Earth's surface of 1000 km or less. Geosynchronous satellites, however, orbit at an altitude of 35790 km above Earth's surface. How much more energy is required to launch a 415 kg satellite into a geosynchronous orbit than into an orbit 1000 km above the surface of Earth?
A geosynchronous orbit is a high-Earth orbit that allows satellites to match Earth's rotation. There is a 500-kg satellite working on the geosynchronous orbit. If this satellite transfers to a new orbit with half the height of the geosynchronous orbit, find (a) the height of the new orbit, (b) percentage change of the radius of the satellite orbit.
Find the height H of a geosynchronous satellite above the surface of the earth. You may well want to find the radius of the orbit R first. You may use the following constants: The universal gravitational constant G is 6.67×10−11Nm2/kg2. The mass of the earth is 5.98×1024kg. The mass of the satellite is 2.10×102kg. The radius of the earth is 6.38×106m. Give the height of the orbit above the surface in km to three significant digits.
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A satellite is in orbit around Earth at a height of 120 km above Earth’s surface. Find the orbital speed of the satellite. (Mass of the earth is 6*1024 kg and the radius of Earth is 6371 km)
A 270 kg satellite is orbiting on a circular orbit 6180 km above the Earth's surface. Determine the speed of the satellite. (The mass of the Earth is 5.97×1024 kg, and the radius of the Earth is 6370 km.)
If a satellite circulate around the earth at a height of 5,113.68 km above the earth's surface, given the earth radius is 3958.8 miles and mass is 5.98 x1024 kg, use G=6.67x 10-11 Nm2/kg2, find the period of this satellite in unit hours?
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 364 km above the earth's surface, while that for satellite B is at a height of 880. km. Find the orbital speed for satellite A and satellite B. (a) VA = (b) VB =
A geosynchronous satellite is placed above the equator and orbiting around the earth to facilitate communication around the world. (You may consider that the mass of the satellite is m, mass of the earth is M(6x1024 kg), center-to-center distance between the satellite and the earth is r, radius of the earth is R(6.4×106 m), and the universal gravitational constant G = 6.67x10-11 N.m2/kg2.) Satellite Earth Applying newton's 2nd law, write an equation describing the circular motion of the satellite. (4...