Question

A group of 10 people agree to meet for lunch at a cafe between 12 noon...

A group of 10 people agree to meet for lunch at a cafe between 12 noon and 12:15 P.M. Assume that each person arrives at the cafe at a time uniformly distributed between noon and 12:15 P.M., and that the arrival times are independent of each other.

Jack and Jill are two members of the group. Find the probability that Jack arrives less than two minutes before Jill.

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A group of 10 people agree to meet for lunch at a cafe between 12 noon...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (1 point) A man and a woman agree to meet at a cafe about noon. If...

    (1 point) A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11 : 40 and 12 : 15 and if the woman independently arrives at a time uniformly distributed between 11 : 50 and 12:40, what is the probability that the first to arrive waits no longer than 10 minutes?

  • Problem 4 Bob and Alice plan to meet between noon and 1 pm for lunch at the cafeteria Bob's arrival time, denoted by X, measured in minutes after 12 noon, is a uniform random variable betrwen 0 a...

    Problem 4 Bob and Alice plan to meet between noon and 1 pm for lunch at the cafeteria Bob's arrival time, denoted by X, measured in minutes after 12 noon, is a uniform random variable betrwen 0 and Go minutes. The same for Alice's amial time, denoted by Y Bob's and Alice's arrival times are independent. We are interested in the waiting time i. What is the probability that W 10 if X 15? ii. What is the probability that...

  • Previous Problem Problem List Next Problem (1 point) A man and a woman agree to meet...

    Previous Problem Problem List Next Problem (1 point) A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10 and if the woman independently arrives at a time uniformly distributed between 11:55 and 12: 35, what is the probability that the first to arrive waits no longer than 5 minutes? 1/3 Preview My Answers Submit Answers

  • Two people, trying to meet, arrive at times independently and uniformly distributed between noon and 1pm....

    Two people, trying to meet, arrive at times independently and uniformly distributed between noon and 1pm. Find the expected length of time that the first waits for the second.Here is the "bottom formula" Apply the bottom formula on P2.8. If we measure time in hours starting from noon, then each arrival time is uniformly distributed in [0,1], so the joint density of the two arrival times (X,Y) is f(x,y) = 1 for 0 sx S1,0 sys 1. How to express...

  • Marc and Jane have agreed to meet for lunch between noon and 1:00 p.m. Denote Jane's...

    Marc and Jane have agreed to meet for lunch between noon and 1:00 p.m. Denote Jane's arrival time from noon by X, Marc's by Y, and suppose X and Y are independent with probability density functions. Mariginal pdf of X: 10x^9 0<x<1 Marginal pdf of Y: 7y^6 0<y<1 Find the expected amount of time Jane would have to wait for Marc to arrive. Round your answer to 4 decimal places. *Please show steps, this was a two part problem but...

  • Problem #4: A man and woman agree to meet at a certain location at 12:33 pm....

    Problem #4: A man and woman agree to meet at a certain location at 12:33 pm. If the man arrives at a time that is uniformly distributed between 12:21 pm and 12:46 pm, and if the woman arrives independently at a time that is uniformly distributed between 12:00noon and 1:00 pm, what is the probability that the man arrives first? Problem #4: Enter your answer symbolically, as in these examples Just Save Submit Problem #4 for Grading

  • P2.10 Interview question Two people, trying to meet, arrive at times independently and uniformly distributed between...

    P2.10 Interview question Two people, trying to meet, arrive at times independently and uniformly distributed between noon and 1pm. Find the expected length of time that the first waits for the second. Problem 4 Do P2.10. Apply the bottom formula on P2.8. If we measure time in hours starting from noon, then each arrival time is uniformly distributed in [0,1], so the joint density of the two arrival times (x, y) is/(x, y) 1 for 0 s x s 1,0...

  • 2. Arrival times. Imagine you live in ancient times, before telephones. In each of the following,...

    2. Arrival times. Imagine you live in ancient times, before telephones. In each of the following, you plan to meet a friend, and your arrival times are independent random variables. For each situation, compute the probability you end up meeting each other. (a) Each of you arrives at your meeting spot at an independent uniformly distributed time between 8 and 9 pm, and wait for 20 minutes. (b) Each of you arrives at an independent exponentially distributed time (with rate1/hour)...

  • MATH REASON OF PROBABILITY Sonia and Natasha are supposed to meet at a certain location around...

    MATH REASON OF PROBABILITY Sonia and Natasha are supposed to meet at a certain location around 5:30 pm. Sonia arrives at some time uniformly distributed between 5:00 pm and 6:00 pm, while Natasha arrives at some time uniformly distributed between 5:15 pm and 6:00 pm. Given that Natasha arrives first, what is the probability that she will not have to wait for more than 10 minutes for Sonia? Hint. Let X be the arrival time (in minutes since 5 pm)...

  • Two people combine to meet in a certain place between 12.00 h and 13.00 h. They...

    Two people combine to meet in a certain place between 12.00 h and 13.00 h. They also combine that each one will wait “a” hours, 0 <a <1, for the arrival of the other. Assuming that the arrivals of the two people are independent and unifomly distributed (in the interval of 12h00 to 13h00), find: (a) the probability that they will actually meet, (b) the value of “a” so that they may meet at a probability of 0,84.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT