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(1 point) A man and a woman agree to meet at a cafe about noon. If...
Previous Problem Problem List Next Problem (1 point) A man and a woman agree to meet...
Previous Problem Problem List Next Problem (1 point) A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10 and if the woman independently arrives at a time uniformly distributed between 11:55 and 12: 35, what is the probability that the first to arrive waits no longer than 5 minutes? 1/3 Preview My Answers Submit Answers
A group of 10 people agree to meet for lunch at a cafe between 12 noon...
A group of 10 people agree to meet for lunch at a cafe between 12 noon and 12:15 P.M. Assume that each person arrives at the cafe at a time uniformly distributed between noon and 12:15 P.M., and that the arrival times are independent of each other. Jack and Jill are two members of the group. Find the probability that Jack arrives less than two minutes before Jill.
Problem #4: A man and woman agree to meet at a certain location at 12:33 pm....
Problem #4: A man and woman agree to meet at a certain location at 12:33 pm. If the man arrives at a time that is uniformly distributed between 12:21 pm and 12:46 pm, and if the woman arrives independently at a time that is uniformly distributed between 12:00noon and 1:00 pm, what is the probability that the man arrives first? Problem #4: Enter your answer symbolically, as in these examples Just Save Submit Problem #4 for Grading
Two people, trying to meet, arrive at times independently and uniformly distributed between noon and 1pm....
Two people, trying to meet, arrive at times independently and
uniformly distributed between noon and 1pm. Find the expected
length of time that the first waits for the second.Here
is the "bottom formula"
Apply the bottom formula on P2.8. If we measure time in hours starting from noon, then each arrival time is uniformly distributed in [0,1], so the joint density of the two arrival times (X,Y) is f(x,y) = 1 for 0 sx S1,0 sys 1. How to express...
P2.10 Interview question Two people, trying to meet, arrive at times independently and uniformly distributed between...
P2.10 Interview question Two people, trying to meet, arrive at times independently and uniformly distributed between noon and 1pm. Find the expected length of time that the first waits for the second. Problem 4 Do P2.10. Apply the bottom formula on P2.8. If we measure time in hours starting from noon, then each arrival time is uniformly distributed in [0,1], so the joint density of the two arrival times (x, y) is/(x, y) 1 for 0 s x s 1,0...
Problem Six (Continuous Joint Random Variables) (A) Suppose Wayne invites his friend Liz to brunch at...
Problem Six (Continuous Joint Random Variables)
(A) Suppose Wayne invites his friend Liz to brunch at the Copley
Plaza. They are coming from separate locations and agree to meet in
the lobby between 11:30am and 12 noon. If they each arrive at
random times which are uniformly distributed in the interval, what
is the probability that the longest either one of them waits is 10
minutes?
Hint: Letting ? and ? be the time each of them arrives in
minutes...
3. Buses arrive at a specified stop at 15-minute intervals starting at 7 A.M. That is,...
3. Buses arrive at a specified stop at 15-minute intervals starting at 7 A.M. That is, they arrive at 7, 7:15, 7:30, 7:45, and so on. If a passenger arrives at the stop at a time that is uniformly distributed between 7 and 7:40, find the probability that he waits more than 10 minutes for a bus.
MATH REASON OF PROBABILITY Sonia and Natasha are supposed to meet at a certain location around...
MATH REASON OF PROBABILITY Sonia and Natasha are supposed to meet at a certain location around 5:30 pm. Sonia arrives at some time uniformly distributed between 5:00 pm and 6:00 pm, while Natasha arrives at some time uniformly distributed between 5:15 pm and 6:00 pm. Given that Natasha arrives first, what is the probability that she will not have to wait for more than 10 minutes for Sonia? Hint. Let X be the arrival time (in minutes since 5 pm)...
Question 2: (11 pts) A show is scheduled to start at 9 AM, 9.30 AM and 10 AM. Once the show start...
Question 2: (11 pts) A show is scheduled to start at 9 AM, 9.30 AM and 10 AM. Once the show starts, the gate will be closed. A visitor will arrive at the gate a time uniformly distributed between 8.30 AM and 10 AM. Determine (a) Probability density function of the time (in minutes) between arrival and 8.30 AM and plot. (b) Cumulative distribution function of the time (in minutes) between arrival and 8.30 AM and plot. (c) Mean and...
Problem 4 Bob and Alice plan to meet between noon and 1 pm for lunch at the cafeteria Bob's arrival time, denoted by X, measured in minutes after 12 noon, is a uniform random variable betrwen 0 a...
Problem 4 Bob and Alice plan to meet between noon and 1 pm for lunch at the cafeteria Bob's arrival time, denoted by X, measured in minutes after 12 noon, is a uniform random variable betrwen 0 and Go minutes. The same for Alice's amial time, denoted by Y Bob's and Alice's arrival times are independent. We are interested in the waiting time i. What is the probability that W 10 if X 15? ii. What is the probability that...
Previous Problem Problem List Next Problem (1 point) A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10 and if the woman independently arrives at a time uniformly distributed between 11:55 and 12: 35, what is the probability that the first to arrive waits no longer than 5 minutes? 1/3 Preview My Answers Submit Answers
Problem #4: A man and woman agree to meet at a certain location at 12:33 pm. If the man arrives at a time that is uniformly distributed between 12:21 pm and 12:46 pm, and if the woman arrives independently at a time that is uniformly distributed between 12:00noon and 1:00 pm, what is the probability that the man arrives first? Problem #4: Enter your answer symbolically, as in these examples Just Save Submit Problem #4 for Grading
Two people, trying to meet, arrive at times independently and
uniformly distributed between noon and 1pm. Find the expected
length of time that the first waits for the second.Here
is the "bottom formula"
Apply the bottom formula on P2.8. If we measure time in hours starting from noon, then each arrival time is uniformly distributed in [0,1], so the joint density of the two arrival times (X,Y) is f(x,y) = 1 for 0 sx S1,0 sys 1. How to express...
P2.10 Interview question Two people, trying to meet, arrive at times independently and uniformly distributed between noon and 1pm. Find the expected length of time that the first waits for the second. Problem 4 Do P2.10. Apply the bottom formula on P2.8. If we measure time in hours starting from noon, then each arrival time is uniformly distributed in [0,1], so the joint density of the two arrival times (x, y) is/(x, y) 1 for 0 s x s 1,0...
Problem Six (Continuous Joint Random Variables)
(A) Suppose Wayne invites his friend Liz to brunch at the Copley
Plaza. They are coming from separate locations and agree to meet in
the lobby between 11:30am and 12 noon. If they each arrive at
random times which are uniformly distributed in the interval, what
is the probability that the longest either one of them waits is 10
minutes?
Hint: Letting ? and ? be the time each of them arrives in
minutes...
3. Buses arrive at a specified stop at 15-minute intervals starting at 7 A.M. That is, they arrive at 7, 7:15, 7:30, 7:45, and so on. If a passenger arrives at the stop at a time that is uniformly distributed between 7 and 7:40, find the probability that he waits more than 10 minutes for a bus.
Question 2: (11 pts) A show is scheduled to start at 9 AM, 9.30 AM and 10 AM. Once the show starts, the gate will be closed. A visitor will arrive at the gate a time uniformly distributed between 8.30 AM and 10 AM. Determine (a) Probability density function of the time (in minutes) between arrival and 8.30 AM and plot. (b) Cumulative distribution function of the time (in minutes) between arrival and 8.30 AM and plot. (c) Mean and...
Problem 4 Bob and Alice plan to meet between noon and 1 pm for lunch at the cafeteria Bob's arrival time, denoted by X, measured in minutes after 12 noon, is a uniform random variable betrwen 0 and Go minutes. The same for Alice's amial time, denoted by Y Bob's and Alice's arrival times are independent. We are interested in the waiting time i. What is the probability that W 10 if X 15? ii. What is the probability that...
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