The pressure of a sample of argon gas was increased from 3.68 atm to 8.52 atm...
The pressure of a sample of argon gas was increased from 3.68 atm to 8.52 atm at constant temperature. If the final volume of the argon sample was 15.5 L, what was the initial volume of the argon sample? Assume ideal behavior.
Homework Answers
P1 = 3.68 atm
V1 = ?
changes to
P2 = 8.52 atm
V2= 15.5 L
according to ideal gas law equation.
PV = nRT
given temperature is constant.
PV = constant
P1V1 = P2V2
V1 = P2V2/P1
= 8.52×15.5/3.68
= 35.89 L
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