. A spherical drop of oil has a mass of 20.5 ug and a radius of 1.74 mm. Given that the volume of a sphere is 4 3 pr 3 , calculate the density of the oil in kg/m3
r = 1.74 mm
= 1.74*10^-3 m
volume = (4/3)*pi*r^3
= (4/3)*3.14*(1.74*10^-3 m)^3
= 2.21*10^-8 m^3
mass = 20.5 ug
= 2.05*10^-5 g
Now use:
density = mass / volume
= (2.05*10^-5 g)/(2.21*10^-8 m^3)
= 928 g/m^3
= 0.928 Kg/m^3
Answer: 0.928 Kg/m^3
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