Question

Write a short C++ program that prompts the user for a series of ten scores in the range of  0-10 and adds them into a total. Check to make sure the numbers that are entered are actually in the proper 0-10 range.

If a 10 is entered then add the ten to the total then double the total to that point.   If a 5 is entered then add five to the total then divide the total by 2 (throwing away any remainders) to that point.  

So if the total was 7 and a 10 was enter then the new total would be (7+10)*2 = 34.. If then a 5 was entered after that then the new total would be (34+5)/2 = 19.

At the end of the loop, divide the final total by 10 to produce a type of average.

If the overall total itself is above 100 at the end then also print out "Test Warrior".     '

If the overall average is above 6 at the end but the score is not above 100 then print out "Good Job".  

Answer 1

#include<iostream>
using namespace std;
int main(){
/**
* Integer variables are declared below as per requirement
* n : It will store the values entered by user
* counter : It will store the count of valid values entered by user
* sum : It will store the summation of the values entered
*/
int n, counter=0,sum=0;

/**
* Following while loop runs until all the 10 values are not scanned
*/
while(true){
/**
* Check if counter is 10 or no.
*/
if(counter==10){
break;
}

/**
* Prompting user to enter the value in range 0-10
*/
cout<<"Enter any value in range 0-10: ";
cin>>n;

/**
* Check if n is in range or no
*/
if(n>=0 && n<=10){
/**
* Increment the counter by 1
*/
counter++;
if(n==10){
sum = (sum + 10)*2;
}else if(n==5){
sum = (sum + 5)/2;
}
}else{
cout<<"Invalid Value!"<<endl;
}
}/*While loop ends here*/

/**
* Calculating the average
*/
int average = sum/10;

if(sum>100){
cout<<"Test Warrior"<<endl;
}
if(average>6 && sum<=100){
cout<<"Good Job"<<endl;
}

return 0;
}