Question

1. Find the negation the coffee has neither cream or sugar added Group of answer choices...

1. Find the negation

the coffee has neither cream or sugar added

Group of answer choices

a. The coffee has either cream or sugar

b. The coffee has both cream or sugar

c. The coffee has no sugar or cream

d. The coffee is black

2. Find the negation

X = 0 or x = 1

a. x is not equal 1 and x is not equal 0

b. x={0,1}

c. x=2

d. x is not 0,1,2,3

3. Match each numbered item with the most closely related lettered item.

To see the options scroll to the right.

p: Chris can study for his math test

q: Chris can watch football

a. p v q Chris cannot watch football

b. p Chris can study or watch

c. ~p Chris can study for his math test

d. ~q Chris cannot study for his math test

4. Match each numbered item with the most closely related lettered item.

To see the options scroll to the right.

x = −10 is less than or equal to 3   x + 7 = 10

a. The following is a truth table containing truth values for two propositions, p and ~q. Complete the table.

b. Find the negation for the following statement . x + 7 ≠  10

c. Find a proposition that is equivalent . X + 7 = -3

d. The following is a truth table containing truth values for two propositions, p and q. Complete the table.

e. For the following propositions, find a negation. 5 is more than 3.

5. p:Austin can have coffee with cream

q:Austin can have coffee with sugar

write the proposition ~q ν p in sentence form.

a. "Austin can have coffee with sugar only"

b. "Austin can have coffee without sugar or with cream"

c. "Austin can have coffee with cream only"

d. "Austin can't have coffee with cream or sugar"

6. Complete the following truth table for g(A,B)=A v ~B and then find g(1,0).

A B ~B g(A,B)
1 1
1 0
0 1
0 0

a. = 0

b. = -1

c. = 1

d. = 3

7. Complete the following truth table for g(A,B)=A v ~B and then find g(1,1).

A B ~B g(A,B)
1 1
1 0
0 1
0 0

a. = 1

b. = -1

c. = 0

d. = 2

8. Complete the following truth table for f(A,B)= ~A∧∧B and then find f(1,1).

A B ~A f(A,B)
1 1
1 0
0 1
0 0

a. ƒ(1,1) = 0

b. ƒ(1,1) = 1

c. ƒ(1,1) = 2

d. ƒ(1,1) = (1,1)

9. Complete the following truth table for f(A,B)= ~A∧∧B and then find f(1,0).

A B ~A f(A,B)
1 1
1 0
0 1
0 0

a. ƒ(1,0) = 1

b. ƒ(1,0) = -1

c. ƒ(1,0) = 0

d. ƒ(1,0) = 1,1

10. Complete the following truth table for f(A,B)= ~A∧∧B and then find f(0,0).

A B ~A f(A,B)
1 1
1 0
0 1
0 0

a. ƒ(0,0) = 1

b. ƒ(0,0) = 0

c. ƒ(0,0) = -1

d. ƒ(0,0) = 1,1

11. Consider the two propositions:

p: jane went to the movies.

q: jane went to the beach.

Write the proposition p ν q

a. "Jane went to the movies or the beach"

b. "Jane went to the movies only"

c. "Jane went to the beach only"

d. "Jane did not go to the movies or the beach"

  

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Answer #1

****This requires some effort so please drop a like if you are satisfied with the solution****

1) C The coffee has no sugar or cream

2) A X is not equal to 0 and X is not equal to 1

3) Chris cannot watch football -> ~q

Chris can study or watch -> p v q

Chris can study for his math test -> p

Chris cannot study for his math test -> ~p

4) for a and d truth tables are not given in question.. for b -> negation -> x+7 = 10 e-> negation 5 is less than 3

5) B Austin can have coffee with out sugar or with cream

6)  

A B ~B g(A,B) = A v ~B
1 1 0 1
1 0 1 1
0 1 0 1
0 0 1 0

g(1,0) = 1 option C

7)

A B ~B g(A,B) = A v ~B
1 1 0 1
1 0 1 1
0 1 0 1
0 0 1 0

g(1,1)= 1 option A

8)

A B ~A f(A,B)
1 1 0 0
1 0 0 0
0 1 1 1
0 0 1 0

f(1,1)= 1 option B

9)

A B ~A f(A,B)
1 1 0 0
1 0 0 0
0 1 1 1
0 0 1 0

f(1,0) = 0 option C

10)

A B ~A f(A,B)
1 1 0 0
1 0 0 0
0 1 1 1
0 0 1 0

f(0,0) = 0 option B

11) A Jane went to the movies or the beach.

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