A random sample of 815 adults surveyed resulted in 20% preferred honey to jam/jelly on their...
A random sample of 815 adults surveyed resulted in 20% preferred honey to jam/jelly on their peanut butter sandwich. Find the 99% confidence interval for the proportion of adults that prefer honey.
What is the UL, Upper limit of the confidence interval?
0.233 is not the answer... :(
Homework Answers
Solution :
n = 815
= 0.200
1 - = 1 - 0.250 = 0.750
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 =
0.01
/ 2 = 0.01 / 2 = 0.005
Z/2
= Z0.005 = 2.576
Margin of error = E = Z
/ 2 * 
(( * (1 - )) / n)
= 2.576 * (((0.200 * 0.800) / 815)
= 0.036
A 90 % confidence interval for population proportion p is ,
+ E
0.200 + 0.036
= 0.236
Upper limit = 0.236
Add Answer to:
A random sample of 815 adults surveyed resulted in 20% preferred
honey to jam/jelly on their...
Suppose that a random sample of 20 adults has a mean score of 74 on a...
Suppose that a random sample of 20 adults has a mean score of 74 on a standardized personality test, with a standard deviation of 7. (A higher score indicates a more personable participant.) If we assume that scores on this test are normally distributed, find a 90% confidence interval for the mean score of all takers of this test. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal...
A random sample of 225 adults was given an IQ test. It was found that 105...
A random sample of 225 adults was given an IQ test. It was found that 105 of them scored higher than 100. Based on this, compute a 90% confidence interval for the proportion of all adults whose IQ score is greater than 100. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. What is the lower limit of the 90% confidence interval? What is the upper limit...
A random sample of 125 adults was given an IQ test. It was found that 71...
A random sample of 125 adults was given an IQ test. It was found that 71 of them scored higher than 100. Based on this, compute a 95% confidence interval for the proportion of all adults whose IQ score is greater than 100. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. What is the lower limit of the 95% confidence interval? What is the upper limit...
1, In 1943, an organization surveyed 1100 adults and asked, "Are you a total abstainer from,...
1, In 1943, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?" Of the 1100 adults surveyed, 385 indicated that they were total abstainers. In a recent survey, the same question was asked of 1100 adults and 363 indicated that they were total abstainers. Complete parts (a) and (b) below. (a) Determine the sample proportion for each sample. The proportions of the adults who took the 1943 survey...
o A random sample of 1015 adults in a certain large country was asked "Do you...
o A random sample of 1015 adults in a certain large country was asked "Do you pretty much think televisions are a necessity or a luxury you could do without of the 1015 adults surveyed, 512 indicated that televisions are a luxury they could do without Complete parts (a) through (0) below. Growth andardroge Click to view the standard normal distriton tablete (a) Obtain a point estimate for the population proportion of adults in the country who believe that televisions...
QUESTION # 1 A random sample of 5,280 permanent dwellings on an entire reservation showed that...
QUESTION # 1 A random sample of 5,280 permanent dwellings on an entire reservation showed that 1,634 were traditional hogans. (a)Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find a point estimate for p. (Round your answer to four decimal places.) (b)Find a 99% confidence interval for p. (Round your answer to three decimal places.) lower limit upper limit QUESTION #2 A random sample of 5,100 permanent dwellings on an entire...
A random sample of 915 adults showed that 34% of them are smokers. Based on this...
A random sample of 915 adults showed that 34% of them are smokers. Based on this sample, the 90% confidence interval for the proportion of all adults who are smokers, rounded to four decimal places, is: the lower endpoint is i the upper endpoint is
In a 2012 survey, Gallup asked a random sample of U.S. adults if they would prefer...
In a 2012 survey, Gallup asked a random sample of U.S. adults if they would prefer to have a job outside the home, or if they would prefer to stay home to care for the family and home. Of the 504 males they surveyed, 391 said that they would prefer to have a job outside of the home. Of the 473 females they surveyed, 254 said that they would prefer a job outside of the home. Pm = sample proportion...
In a random sample of 100 eligible voters, 85 preferred candidate A over candidate B. Find...
In a random sample of 100 eligible voters, 85 preferred candidate A over candidate B. Find a 99 percent confidence interval for the proportion p of voters favoring candidate A.
A random sample of 388 married couples found that 280 had two or more personality preferences...
A random sample of 388 married couples found that 280 had two or more personality preferences in common. In another random sample of 562 married couples, it was found that only 36 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 99% confidence interval for...
Suppose that a random sample of 20 adults has a mean score of 74 on a standardized personality test, with a standard deviation of 7. (A higher score indicates a more personable participant.) If we assume that scores on this test are normally distributed, find a 90% confidence interval for the mean score of all takers of this test. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal...
A random sample of 225 adults was given an IQ test. It was found that 105 of them scored higher than 100. Based on this, compute a 90% confidence interval for the proportion of all adults whose IQ score is greater than 100. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. What is the lower limit of the 90% confidence interval? What is the upper limit...
A random sample of 125 adults was given an IQ test. It was found that 71 of them scored higher than 100. Based on this, compute a 95% confidence interval for the proportion of all adults whose IQ score is greater than 100. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. What is the lower limit of the 95% confidence interval? What is the upper limit...
o A random sample of 1015 adults in a certain large country was asked "Do you pretty much think televisions are a necessity or a luxury you could do without of the 1015 adults surveyed, 512 indicated that televisions are a luxury they could do without Complete parts (a) through (0) below. Growth andardroge Click to view the standard normal distriton tablete (a) Obtain a point estimate for the population proportion of adults in the country who believe that televisions...
A random sample of 915 adults showed that 34% of them are smokers. Based on this sample, the 90% confidence interval for the proportion of all adults who are smokers, rounded to four decimal places, is: the lower endpoint is i the upper endpoint is
In a 2012 survey, Gallup asked a random sample of U.S. adults if they would prefer to have a job outside the home, or if they would prefer to stay home to care for the family and home. Of the 504 males they surveyed, 391 said that they would prefer to have a job outside of the home. Of the 473 females they surveyed, 254 said that they would prefer a job outside of the home. Pm = sample proportion...
Most questions answered within 3 hours.
-
4. Without doing any calculations, predict whether the observed
∆T would increase, decrease or remain the...
asked 30 minutes ago -
Based on the range, which of the following sets of scores has
the greatest variability? 3,...
asked 1 hour ago -
Ripples in a pond travel at a velocity of 3 m/s with one peak
passing a...
asked 1 hour ago -
A man stands on the roof of a building of height 13.0 mm and
throws a...
asked 1 hour ago -
The extent to which assets are financed by borrowed funds and
other liabilities is indicated by:...
asked 2 hours ago -
Explain in detail
Germany is the fifth largest economy
explain what goods and services Germany specializes...
asked 2 hours ago -
The density of platinum is 21.45 g/mL. If a cube of platinum
with a mass of...
asked 2 hours ago -
Accounts Receivable
Sales
A/R Posting
Extended Sales Invoice
Packing Slip
Compare invoice to packing slip 2...
asked 2 hours ago -
Michaella, age 23, is a full-time law student and is claimed by
her parents as a...
asked 2 hours ago -
Why are polymers not typically casted into products?
asked 3 hours ago -
When rolling a die 129 times, what is the probability of rolling
a 6 no more...
asked 3 hours ago -
4. A call option currently sells for $7.75. It has a strike
price of $85 and...
asked 3 hours ago