One piece of silver jewelry, at T1= 985.8°C, has three times the mass of another piece...
One piece of silver jewelry, at T1= 985.8°C, has three times the mass of another piece (3m1= m2) at TI= 120.0 °C. Both are placed in a calorimeter of negligible heat capacity. What is the final temperature inside the calorimeter (C = 0.233 J/g°C)?
Homework Answers
Given,
One piece of silver jewelry has three times the mass of another piece(3m1 = m2)
Assume, m1 = 1 g
Then, 3 x 1g = m2
m2 = 3 g
C = 0.233 J/g oC
The initial temperature of silver jewelry with mass (m1) = 985.8 oC
The initial temperature of silver jewelry with mass (m2) = 120.0 oC
Now,
Heat loss by the silver jewelry with mass m1 = Heat gain by the silver jewelry with mass m2
- ( m1 x C x 
T) =
(m2 x C x T)
Assume, Tf is the final temperature inside the calorimeter,
C is the specific heat capacity of silver jewelry and is same on both the side, thus we can neglect it.
- [ 1g x (Tf - 985.8) oC] = [ 3g x (Tf - 120.0) oC]
-Tf + 985.8 = 3Tf - 360.0
Tf = 336.45 oC
The final temperature inside the calorimeter is 336.45 oC
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